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DerKrebs [107]
3 years ago
15

Write the mixed number as an improper fraction. 3 3/5

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
7 0

Answer:

18/5

Step-by-step explanation:

To find the improper fraction change the whole number into a fraction:

3 *5/5 = 15/5 which is the same as 3

then add the remaining 3/5 to the fraction

15/5 + 3/5

= 18/5

Westkost [7]3 years ago
6 0

Answer:

3 3/5 as an improper fraction = 18/5

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98-x2=0 solve this with the quadratic formula
Mars2501 [29]

Answer:

             x∈{-7√2, 7√2}

Step-by-step explanation:

98-x^2=0\\\\-x^2+98=0\\\\a=-1\,,\ \ b=0\,,\ \ c=98\\\\x_1=\dfrac{-0-\sqrt{0^2-4\cdot(-1)\cdot98}}{2\cdot(-1)}=\dfrac{-\sqrt{4\cdot49\cdot2}}{-2}=\dfrac{-2\cdot7\sqrt{2}}{-2}=7\sqrt2\\\\x_2=\dfrac{-0+\sqrt{0^2-4\cdot(-1)\cdot98}}{2\cdot(-1)}=\dfrac{2\cdot7\sqrt{2}}{-2}=-7\sqrt2

7 0
3 years ago
Can you solve this? I need help. I don't understand.
ZanzabumX [31]

Answer:

2 sqrt(5) OR 4.5

Step-by-step explanation:

You have to know Pythagorean theorem to solve this question.

a^2 + b^2 = c^2

To use this theorem you have to have a right triangle. There are two right triangles in your image. The lower (larger) one has two sides labeled, so you can use Pythagorean thm to find the third side. There's a short cut, bc some right triangles have easy-to-memorize lengths of the sides. 3-4-5 is one of these number sets. A multiple of this is 6-8-10. We could've solved:

b^2 + 8^2 = 10^2

But it would've come out the same. The unlabeled side is 6.

We can use the 6 and the 4 on the smaller right triangle and use the Pythagorean thm again to solve for x.

4^2 + x^2 = 6^2

16 + x^2 = 36 subtract 16 from both sides.

x^2 = 20

Take the square root of both sides.

sqrt (x^2) = sqrt 20

x = 2 sqrt(5) which is approximately 4.472.

2 sqrt(5) is an exact answer if that is what they are asking for. 4.472 is an approximation to the nearest thousandth. It would be 4.47 to the nearest hundredth or 4.5 to the nearest tenth.

8 0
2 years ago
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Sophie [7]

Answer:

The answer is in the above attachment.

8 0
2 years ago
Read 2 more answers
I turn my dial on my stove 45degrees from the start position if i continue to turn the dial, how many degrees further will i nww
AveGali [126]

Answer:

315 degrees

Step-by-step explanation:

Assume that the dial is a perfect circle and therefore makes a full 360 degree rotation. If the dial is already turned 45 degrees, the rotation angle required to return all the way to the initial position is:

A = 360 - 45\\A=315\ degrees

You will need to rotate 315 degrees.

6 0
3 years ago
Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
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