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3 years ago

List at least 5 professions for people working in the Information/Communication fields.

Computers and Technology

1 answer:

MrRissso [65]3 years ago

5 0

Answer:

telephone servicer, mobile phone servicer, televsion servicer, computer servicer, laptop servicer

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To enforce the concept of separating class definition from its function implementations, where should the function implementatio

zzz [600]

D(in a .c file ) because that is where it should be placed :)

4 0

2 years ago

What is intensity? this is for digital arts

vladimir2022 [97]

Intensity is the brightness of a color. When a color is not mixed with any black or white it is at full intensity; Also called a pure hue. You can also change the intensity of a color by adding its complimentary color.

Hope this helps

6 0

3 years ago

Code a call to the function anotherFunc passing the array myints.

mario62 [17]

Answer:

d)anotherFunc(myints);

Explanation:

When we call a function we just have to pass the names of the arguments to the function.In case of arrays we also just have to pass the name of the array.We don't have to worry about the square brackets.So the function call will be like this.

anotherFunc(myints);

Hence the answer is option d.

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3 years ago

When studying an information system, illustrations of actual documents should be collected using a process called _____.

Oliga [24]

When studying an information system, illustrations of actual documents should be collected using a process called sampling. Correct answer: D
This process systematically selects representative elements of a population with the goal to get representative and useful information about the population as a whole and it is useful when data sets that are too large to efficiently analyze in full.

6 0

3 years ago

1. How many bits would you need to address a 2M × 32 memory if:

Dominik [7]

Answer:

a) 23 b) 21
a) 43 b) 42
a) 0 b) 0

Explanation:

1) How many bits is needed to address a 2M * 32 memory

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8; L = ( 2M * 32 ) / 8 = 2M * 4

hence number of bits = log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

2) How many bits are required to address a 4M × 16 main memory

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

3) How many bits are required to address a 1M * 8 main memory

1M = 1^1 * 1^20 , item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0

3 years ago