<span>sin A cos B=1/2[sin(A-B)+sin(A+B)]
sin(at)*cos(2at)=1/2[sin(3at)-sin(at)]</span>
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Answer:
-45
Step-by-step explanation:
2/3x - 11 = x + 4
- I created an inequality representing the above statement first. This makes things look less complicated than what the question is asking.
2/3x = x + 15
- solve for x. I started by adding 11 to both sides.
-1/3x = 15
- multiply both sides by -3
x = -45
Answer:
20
Step-by-step explanation:
Assuming that is 3 1/3 C per batch.
(3 1/3)(6)
(10/3)(6)
(10)(2)
20