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3 years ago

What is the solution to the system of equation

Mathematics

1 answer:

maksim [4K]3 years ago

4 0

Answer:

D. (2 , 1)

Step-by-step explanation:

STEP 1: Replace all occurrences of $y$ with $-3x+7$ in each equation.

$-x+14=12\\y=-3x+7$

STEP 2: Solve for $x$ in the first equation.

$x=2\\y=-3x+7$

STEP 3: Replace all occurrences of $x$ with $2$ in each equation.

$y=1\\x=2$

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segment M'N' has endpoints located at M' (−2, 0) and N' (2, 0). It was dilated at a scale factor of 2 from center (2, 0). Which

Anna11 [10]

Answer:

A. MN is located at M 0,0) and N (2, 0) is half the length of M'N'.

Step-by-step explanation:

MN was dilated with a factor 2 is is half the length of M'N'.

7 0

3 years ago

Read 2 more answers

choose five ordered pairs whose first and second coordinates are equal. plot these points and connect them. what kind of figure

Effectus [21]

Answer:

The figure is a straight line.

The figure lies in the first and the third quadrants.

Step-by-step explanation:

Take five ordered pairs as $(1,1),(2,2),(-1,-1),(-2,-2),(3,3)$

Here, the first and second coordinates are equal.

Now, plot these points and connect them.

From the graph, it can be observed that the figure is a straight line.

Also, the figure lies in the first and the third quadrants.

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5 0

3 years ago

The perimeter of a rectangle is 34 units and its width is 6.5 units

IgorC [24]

Since you technically didn't ask for anything to be solved for, this problem is now solved. Since these types of problems are normally solving for legnth if width is given and vice versa, I will solve for legnth.

perimiter=legnth+legnth+width+width or
p=l+l+w+w
p=2l+2w
subsitute w=6.5 and p=34
34=2l+2(6.5)
34=2l+13
subtract 13 from both sides
21=2l
divide by 2
10.5=l

legnth=10.5 units

5 0

3 years ago

Work out the volume of this sphere.

navik [9.2K]

Answer:

Volume of the sphere ( V ) = 1436.02 cm³

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the radius of the sphere r = 7 cm

Volume of the sphere

$V = \frac{4}{3} \pi r^{3}$