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puteri [66]
4 years ago
9

5,342 round to hundred place value

Mathematics
2 answers:
tester [92]4 years ago
8 0
This is what you have to do 5,342 / 100 = 53.42
slava [35]4 years ago
6 0
I think its 5,300 im not sure how u do it in 5th grade if its right ok but if it wrong idk cuz idr anything from 5th 

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HELLPPP DUE TODAY AT 4
Natalka [10]

Answer:

2 and 2/3 for the first question

-1/8 for the second one

-1/5 for the third one

ive never done this type of question or maybe it was too long ago for me to remember but out of this answer choices i would guess that its the last one

this is 3

Step-by-step explanation:

you add the numerators which is the top number in order to get 2 and 2/3rds

you subtract 5 from 4 to get -1/8

same situation as the last one, subtract 15 from 11 to make it a negative 4/20 and then simplify that by dividing it by four to get 1/5th

this one i dont understand or remember how to do very well but if i had to guess its the last answer choice

this one you add 3/4 plus 1/4 in order to get 4/4 or rather 1, so basically its asking what 1+1+1 is which is 3

5 0
3 years ago
All the cubes between 1000 and 3000
beks73 [17]
It would be 10^3 = 1000, 11^3= 1331, 12^3 = 1728, 13^3 = 2197, 14^3 = 2,744
5 0
4 years ago
Find the slope of the line containing the two points (1,-1) and (-5,-3)
Strike441 [17]
Slope =(-3 + 1)/(-5 - 1) = -2/-6 = 1/3

answer
1/3
4 0
4 years ago
A consumer group wants to know if an automobile insurance company with thousands of customers has an average insurance payout fo
zhenek [66]

Answer:

E. No, it is not appropriate because the distribution of the population is skewed and the sample size is not large enough to satisfy the condition that the sampling distribution of the sample mean be approximately normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

Standard deviation larger than the sample mean means that the distribution is skewed.

By the Central Limit Theorem, when the distribution is skewed, normality is assumed for samples sizes of 30 or higher. In this question, the sample is of 18, which is less than 30, so the hypothesis test is not appropriated, and the correct answer is given by option E.

7 0
3 years ago
Solve for the letter t
rosijanka [135]
T=34.34

explanation: solve for t by simplifying both sides of the equation, then isolating the variables.
7 0
3 years ago
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