Percent change = [(45 - 60) / 60] x 100 = -25 % (decrease)
Answer:

Step-by-step explanation:
Given
When mass = 4kg; Acceleration = 15m/s²
Required
Determine the acceleration when mass = 10kg, provided force is constant;
Represent mass with m and acceleration with a
The question says there's an inverse variation between acceleration and mass; This is represented as thus;

Convert variation to equality
; Where F is the constant of variation (Force)
Make F the subject of formula;

When mass = 4kg; Acceleration = 15m/s²


When mass = 10kg; Substitute 60 for Force



Divide both sides by 10


<em>Hence, the acceleration is </em>
<em />
Parallel lines will have the same slope
y - y1 = m(x - 1)
slope(m) = 1/4
(5,5)...x1 = 5 and y1 = 5
now we sub
y - 5 = 1/4(x - 5) <==== ur parallel line
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perpendiculr lines will have a negative reciprocal slope. To find the negative reciprocal, u flip the number and change the sign. So the negative reciprocal of 1/4 is -4....see how I flipped 1/4 and made it 4/1...then changed the sign making it -4/1 or just -4. That will be ur slope of the perpendicular line.
y - y1 = m(x - x1)
slope(m) = -4
(5,5)...x1 = 5 and y1 = 5
now we sub
y - 5 = -4(x - 5) <=== ur perpendicular line
No because it doesn't make sense <span />
Hope i help <span>42/2= 21
21 / 3 = 7
Answer=2 x 3 x 7</span>