Answer:
The angles are 69.2 degrees and 20.8 degrees
Step-by-step explanation:
Complementary angles, when added together, = 90°
We’ll call the first unknown angle a and the second angle b
b = a - 48.4
a + b = 90
So let’s substitute in for b in the second equation:
a + a - 48.4 = 90
2a - 48.4 = 90
2a = 138.4
a = 69.2
69.2 - 48.4 = 20.8 = b
Now, does a + b = 90?
69.2 + 20.8 = 90
Lmk if you have questions
1. Rewrite the system:
x+12y=68 (i)
x=8y-12 (ii)
2. Let's substitute the equation (ii) into the equation (i):
x+12y=68
(8y-12)+12y=68
3. Then, you have:
8y-12+12y=68
4. When you clear "y", you have:
20y-12=68
20y=68+12
20y=80
y=80/20
y=4
5. You already have the value of "y". Now, you must substitute this value into the equation (ii):
x=8y-12
x=8(4)-12
x=32-12
x=20
6. Therefore, the result is:
x=20
y=4
Answer:
1/6a-1/6
Step-by-step explanation:
-2/3 transferred into 6th's is -4/6. You combine like terms, -4/6a+5/6a=1/6a
Then since -1/6 doesn't have a like term, it stays the same.
We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:
We have then a total number of grades of 39.
The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.
Then, for grade A, the relative frequency (RF) will be:
This will be the fraction of the total grades that are A. Represented as a percentage will be 10.26%, rounded to two decimal places.
Now, to complete the table we do the same for the other frequencies:
For grade B:
For grade C:
For grade D:
For grade F:
