I need help please :,(

Mathematics

1 answer:

Ede4ka [16]3 years ago

4 0

I think it’s the first one

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60 = x^2 + 4x Sixty equals x squared plus four times x.

ss7ja [257]

Answer:

Solve by moving 60 to the right. Then factor to get x=-10 or 6.

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3 years ago

A man on a 135-ft vertical cliff looks down at an angle of 16°13' and sees his friend.

iren2701 [21]

A) Use the trigonometric function and ratio cos(x) = A/H. (Adjacent/Hypotenuse)
1. cos(x) = 135/H
2. H*cos(16°) = 135
3. H = 135/cos(16°)
***Make sure calculator is in degree mode***
4. H = 140.44 ft (rounded to two decimal places)
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b) Use the function and ratio tan(x) = O/A (Opposite/Adjacent)
1. tan(x) = O/A
2. tan(16°) = O/135
3. 135*tan(16°) = O
4. O = 38.71 ft (two decimal places)

Good luck!

6 0

3 years ago

-6x^3-4x^2+15x-5 - -x^2-8x+14

Ilya [14]

Answer:

-1

Step-by-step explanation:

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3 years ago

Find the value of the constant m √150 - √12m + √54 = 0

Tomtit [17]

Answer:

m is √2

Step-by-step explanation:

${ \tt{ \sqrt{150} - \sqrt{12}m + \sqrt{54} = 0 }} \\ { \tt{ \sqrt{12}m } = \sqrt{150} - \sqrt{54} } \\ { \tt{ (\sqrt{4 \times 3}) m = ( \sqrt{25 \times 6} ) - ( \sqrt{9 \times 6}) }} \\ { \tt{( \sqrt{4 \times 3} )m = 5 \sqrt{6} - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3}m = 5 \sqrt{6} - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3} m = 2 \sqrt{6} }} \\ { \tt{ \sqrt{3} m = \sqrt{6} }} \\ { \tt{ \sqrt{3} m = ( \sqrt{3} \times \sqrt{2} ) }} \\ { \tt{m = \sqrt{2} }}$

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3 years ago

Jenn says there are 2 weeks 5 days left in the year. How many days are left in a year

Law Incorporation [45]

19 days are left in a year because 1 week=7 days which means 2 weeks=14 days 14 +5=19

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3 years ago

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