Answer:
a.- slope= 36
Interpretation : The cable car travels 36 meter per minute
b.- y = 36x + 100
c.- 640 meters
Step-by-step explanation:
a.-
Find slope using the slope formula : 
Plug in the two given points: 
Subtract the numbers : 
Reduce the fraction : 36
b.-
Using the given y-interspet (100) and the slope create an equation: y = 36x + 100
c.-
Using the equation you created plug in 15 for x to find the
distance: y = 36 (15) + 100
Multiply the numbers : y = 540 + 100
Add the numbers : y = 640
First, solve for the x - intercept. To do so, equate y to 0 and solve for x.
0 = 4x - 2, x = 1/2
Second, solve for the y - intercept. Equate x to 0 which will give us,
y = (4)(0) -2, y = -2
Therefore, the x-intercept is 1/2 and y-intercept is -2.
Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
Answer:
We get value of y: y = 2
Step-by-step explanation:
The points (3,5) and (2, y) are on a line with a slope of 3. Find y.
We can find y using formula of finding slope of a line.
The formula is: 
We have 
and Slope = 3
Putting values and finding y
So, we get value of y: y = 2
the more years the money stays invested, the more interest it earns, so clearly, if the compounding cycle is the same for both options, and the rate of 7% is the same as well for both, then the one with more years will give more interest..
so depends on what "best" means in this context, but if it's more interest earned, 3 years gives more interest than 2 years of course.
