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Diano4ka-milaya [45]
3 years ago
14

What is the annual interest rate for an account that compounds monthly at a rate of 2.5%?

Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0

Answer:

D 2.55%

Step-by-step explanation:

:)

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I think its B. ?????

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The product of Greg's savings and 3 is 57.
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Greg's savings: 19 x 1

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57 / 3 = 19

19 is prime, so Greg's savings has to be 19 x 1.

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A mechanic charges $20.00 an hour, h for labor plus parts. If the parts cost $217.00, write a linear equation that will find the
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2 years ago
Assume that adults were randomly selected for a poll. They were asked if they "favor or oppose using federal tax dollars to fund
ser-zykov [4K]

<u>Testing the hypothesis</u>, it is found that since the <u>p-value of the test is 0.0042 < 0.01</u>, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

At the null hypothesis, it is tested if the <u>proportion is of 0.5</u>, that is:

H_0: p = 0.5

At the alternative hypothesis, it is tested if the <u>proportion is different of 0.5</u>, that is:

H_1: p \neq 0.5

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the value tested at the null hypothesis.
  • n is the sample size.

In this problem, the parameters are given by:

p = 0.5, n = 483 + 398 = 881, \overline{p} = \frac{483}{881} = 0.5482

The value of the test statistic is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}

z = \frac{0.5482 - 0.5}{\sqrt{\frac{0.5(0.5)}{881}}}

z = 2.86

Since we have a <u>two-tailed test</u>(test if the proportion is different of a value), the p-value of the test is P(|z| > 2.86), which is 2 multiplied by the p-value of z = -2.86.

Looking at the z-table, z = -2.86 has a p-value of 0.0021.

2(0.0021) = 0.0042

Since the <u>p-value of the test is 0.0042 < 0.01</u>, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

A similar problem is given at brainly.com/question/24330815

3 0
2 years ago
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