Answer: 2 solutions.
The given equation breaks down into these two equations
3x+12 = 18 and 3x+12 = -18
Basically 3x+12 equal to plus 18 and minus 18. This is due to the fact that something like |x| = 7 means x = 7 or x = -7, ie those x values are exactly seven units away from zero on the number line.
If you want to solve each equation, then
3x+12 = 18
3x = 18-12
3x = 6
x = 6/3
x = 2 is one solution
and
3x+12 = -18
3x = -18-12
3x = -30
x = -30/3
x = -10 is the other solution
Answer:
its the 2nd on on the top row
Step-by-step explanation:
The smallest of the three consecutive integers is 24.
<h3>How to solve algebraic word problems?</h3>
Let the 3 consecutive integers be;
x, y and z
Thus;
y = x + 1
z = x + 2
Now, we are told that their sum is equal to 4 times the largest number minus 29. Thus;
x + x + 1 + x + 2 = 4(x + 2) - 29
3x + 3 = 4x + 8 - 29
4x - 3x = 3 + 21
x = 24
Thus, we can conclude that the smallest of the three consecutive integers is 24.
Read more about algebra word problems at; brainly.com/question/13818690
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.162 kilograms?
How I got my answer:
1.35÷500=.0027
.0027×60=.162
Answer:
A. see below for a graph
B. f(x, y) = f(0, 15) = 90 is the maximum point
Step-by-step explanation:
A. See below for a graph. The vertices are those defined by the second inequality, since it is completely enclosed by the first inequality: (0, 0), (0, 15), (10, 0)
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B. For f(x, y) = 4x +6y, we have ...
f(0, 0) = 0
f(0, 15) = 6·15 = 90 . . . . . the maximum point
f(10, 0) = 4·10 = 40
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<em>Comment on evaluating the objective function</em>
I find it convenient to draw the line f(x, y) = 0 on the graph and then visually choose the vertex point that will put that line as far as possible from the origin. Here, the objective function is less steep than the feasible region boundary, so vertices toward the top of the graph will maximize the objective function.
