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ZanzabumX [31]
3 years ago
5

European rabbits were introduced into australia and quickly spread, reproduced, and became a terrible pest. they eat up to $600

million worth of food and pasture crops annually, and have damaged the populations of many native plants and the populations of animals that eat the plants. twice in the past 50 years, rabbit diseases have been introduced to try to control the population, with some success. this is a case where ________.
Biology
1 answer:
s2008m [1.1K]3 years ago
4 0
This is a case where AN INVASIVE SPECIE HAS REDUCED THE GENETIC DIVERSITY OF INDIGENOUS SPECIE.
An invasive specie is an animal specie that is brought from another ecosystem and is introduced to a new ecosystem. Such invasive species may throw their new habitat into an imbalance as a result of the manner in which they interact with the components of the ecosystem that has been existing in the ecosystem before and that is what happen in the scenario given above.
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____ The bristle worm living with the hermit crab.
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A. Mutualism

Explanation:

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2 years ago
Two different enzymes catalyze the same reaction and both exhibit the same Vmax. When Enzyme A was run with a 40 uM substrate, t
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Answer:

a) k_m = 4.08 uM

  V_{max} = 20.07 uM/min

b) k_m = 8.16 uM

Explanation:

Given that:

For Enzyme A:

the substrate concentration [S] = 40 uM

the initial velocity rate v = 10 uM/min

when it was 4mM, v = 20 uM/min

i.e.

at 4mM = 4000 uM;

Using Michealis -menten equation;

when v = 10

V = \dfrac{V_{max}[S]}{k_m+[S]}

∴

10 = \dfrac{V_{max}\times 40}{k_m + 40}

10 (k_m + 40) = V_{max}40

40V_{max} -10k_m = 400 --- (1)

when v= 20

20= \dfrac{V_{max}\times 4000}{k_m + 4000}

20 (k_m + 4000) = V_{max}4000

4000V_{max} -20k_m = 8000 --- (2)

equating equation (1) and (2):

40V_{max} -10k_m = 400 --- (1)

4000V_{max} -20k_m = 8000 --- (2)

let multiply equation (1) by 100 and equation (2) by 1

4000V_{max} - 1000K_m = 4000

<u>4000V_{max} - 20 k_m = 8000     </u>

  0        -980k_m = 4000

k_m = 4000/-980

k_m = 4.08 uM

replacing the value of k_m into equation (1)

40{V_max } - 10(4.08) = 400

40{V_max } - 40.8 = 400

40{V_max } = 400 +  40.8

40{V_max } = 440.8

V_{max} = 440.8/40

V_{max} = 11.02 uM/min

b)

Since V_{max} of A ie equivalent to that of B; then:

V_{max} of B = 11.02 uM/min

Here;

[S] = 80  uM

V = 10 uM/min

∴

10 = \dfrac{11.02 \times 80}{k_m + 80 }

10(k_m +80) = 881.6

10k_m = 881.6  - 800

10k_m = 81.6

k_m = 81.6/10

k_m = 8.16 uM

8 0
3 years ago
Answer the best you can :))
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