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HACTEHA [7]
3 years ago
7

Problems 13 – 15, write a quadratic function to model each graph. I need help asap please ❤️

Mathematics
1 answer:
krok68 [10]3 years ago
7 0
I vud xu dje y. Susgi cu dew in i de ft fii ok bu commentator bandana cloak misconduct 13-15
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Find the area of a Parallelogram if it was 2 cm and 6 cm
Alex777 [14]
12 cm is your answer

you just multiply 2 times 6 which is 12
6 0
3 years ago
Can somebody please solve this? It's a coordinate thingy
statuscvo [17]

Answer:

Coordinates involve two points. (x,y)

Too find a pair (coordinate), use the x and y lines on the graph and see where the point falls.

For example

Point A is number <em>1</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>y</em><em> </em><em>axis</em>

<em>number</em><em> </em><em>-</em><em>4</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>x</em><em> </em><em>axis</em>

<em>So</em><em>,</em><em> </em><em>you</em><em> </em><em>would</em><em> </em><em>write</em><em> </em><em>the</em><em> </em><em>coordinate</em><em> </em><em>out</em><em> </em><em>at</em><em> </em>

<em>(</em><em>-</em><em>4</em><em>,</em><em>1</em><em>)</em>

The y axis values are the second point, so after you plot all of letters, use the y axis numbers and number them from least to greatest so you can find the mystery word.

6 0
2 years ago
Read 2 more answers
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
What is the constant of proportionality for the relationship in this table? Please answer is you know the solution. Thx
BabaBlast [244]

Answer:4

Step-by-step explanation:use https://www.cymath.com/

3 0
3 years ago
I tried many times to solve this question: Joy makes 6,5 litres soup correct to the nearest 0.5 litres. She serves the soup in 2
Paraphin [41]

Joy makes 6.5 litres soup correct to the nearest 0.5 litres. She serves the soup in 280ml portions correct to the nearest 10ml. 22 people order this soup. Does joy definitely has enough soup to serve the 22 people.

Answer:

Yes, Joy definitely does has enough soup

Step-by-step explanation:

From the question, we know,

Joy make 6.5 litres of soup

Serves it in 280ml portions

Step 1

We convert the portions to liters

1 ml = 0.001 litre

280 ml

= 280ml × 0.001 litre/1 ml

= 0.28litre

Step 2

We divide 6.5 liters by 0.28 to find out how many people can be served

= 6.5 ÷ 0.28

= 23.2142857143 people

We can see that 6.5 liters soup can serve 23 people approximately.

Therefore, Yes, Joy definitely does has enough soup to serve 22 people

4 0
3 years ago
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