Jus look at the picture
2 answers:
Answer:
between 0 and 1
Step-by-step explanation:
The big key to this is that the negative sign in front of the two is NOT in parentheses along with the 2.
We follow the order of operations - PEMDAS - parentheses, exponents, multiplication and division, addition and subtraction.
So, inside the parentheses, the <u>first </u>thing we do is the <u>exponent</u>. We raise 2 to the third power and get 8.
Next, still inside the parentheses, we now multiply by negative 1. That is what putting a negative sign in front of something really is - multiplying by -1.
So now inside the parentheses, we have -8.
-8 raised to the power -2 is one over (-8) raised to the power positive 2.
That is one over 64,
That is more than zero, but less than one.
I have the math written out in an attached picture (I hate the equation writer on this website.) Haha.
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Answer:
Step-by-step explanation:
Given
Bisector: QS
Required
Determine PQR
Since PQR is bisected to PQS and RQS, we have that
Substitute expressions for PQS and RQS
Collect Like Terms
Divide both sides by 3
Solving for PQR;
Substitute 2 for x