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3 years ago

Find the measure of the indicated angle to the nearest degree

Mathematics

1 answer:

hjlf3 years ago

8 0

Answer:

28°

Step-by-step explanation:

sin ? = 19/41

? = arcsin (19/41)

? = 28° (rounded to the nearest degree)

Answered by GAUTHMATH

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3 years ago

Read 2 more answers

5. A tank initially contains 20 lb of salt dissolved in 200-gallon of water. Starting at time t = 0, a solution containing 0.5 l

sladkih [1.3K]

Answer:

(a) Amount of salt as a function of time

$A(t)=100-80e^{-0.02t}$

(b) The time at which the amount of salt in the tank reaches 50 lb is 23.5 minutes.

Step-by-step explanation:

The rate of change of the amount of salt can be written as

$\frac{dA}{dt} =rate\,in\,-\,rate\,out\\\\\frac{dA}{dt}=C_i*q_i-C_o*q_o=C_i*q_i-\frac{A(t)}{V}*q_o\\\\\frac{dA}{dt}=0.5*4-\frac{A(t)}{200}*4\\\\\frac{dA}{dt} =\frac{100-A(t)}{50}=-(\frac{A(t)-100}{50})$

Then we can rearrange and integrate

$\frac{dA}{dt}= -(\frac{A(t)-100}{50})\\\\\int \frac{dA}{A-100}=-\frac{1}{50} \int dt\\\\ln(A-100)=-\frac{t}{50}+C_0\\\\ A-100=Ce^{-0.02*t}\\\\\\A(0)=20 \rightarrow 20-100=Ce^0=C\\C=-80\\\\A=100-80e^{-0.02t}$

Then we have the model of A(t) like

$A(t)=100-80e^{-0.02t}$

(b) The time at which the amount of salt reaches 50 lb is

$A(t)=100-80e^{-0.02t}=50\\\\e^{-0.02t}=(50-100)/(-80)=0.625\\\\-0.02*t=ln(0.625)=-0.47\\\\t=(-0.47)/(-0.02)=23.5$

(c) When t approaches to +infinit, the term e^(-0.02t) approaches to zero, so the amount of salt in the solution approaches to 100 lb.

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3 years ago

Two lines that intersect to form right angle are called

Sergio039 [100]

Answer:

perpendicular

Step-by-step explanation:

When 2 lines intersect at any point, not just in the middle of each (that has nothing to do with it), and they meet to form right angles, the lines are perpendicular to one another and their slopes are opposite reciprocals.

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3 years ago

Find the measure of the indicated angle to the nearest degree​

Find the measure of the indicated angle to the nearest degree