Answer:
y=-5
x=2
Step-by-step explanation:
3x + 3y=-9
3x - 3y=21
-
0+6y=-30
6y=-30
y=-5
3x-15=-9
x=2
Firstly. make your unknown number X.
95% can be represented as 95/100 or 0.95
so 95% of X is 76...
0.95 × X = 0.76
X = 0.76 ÷ 0.95
X = 0.8
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for the second question.
(17 ÷ 20.4) and times it by 100 to get a percentage.
Answer:
The answer for y is 4 units
Step-by-step explanation:
The obvious question to ask in this situation is, “how many miles does Joseph travel on Mondays”? To compute, we each distance: 3 + 6 + 6 = 15.
Joseph travels 15 miles on Mondays.
Another way to work with this situation is to draw a shape that represents Joseph’s travel route and is labeled with the distance from one spot to another.
Notice that the shape made by Joseph’s route is that of a closed geometric figure with three sides (a triangle) (see figure 2). What we can ask about this shape is, “what is the perimeter of the triangle”?
Perimeter means “distance around a closed figure or shape” and to compute we add each length: 3 + 6 + 6 = 15
Our conclusion is the same as above: Joseph travels 15 miles on Mondays.
However, what we did was model the situation with a geometric shape and then apply a specific geometric concept (perimeter) to computer how far Joseph traveled.
Answer:
Step-by-step explanation: 2 4 1 5 2 1 3 1 3 1 3 4 2 44 5 3 i dont know
Answer:
We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:
Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.
we get :
where C(i) is a constant coefficient obviously between 0 and 1.
All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]
So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.
We already know the sum so it is easy to compute the average :
