D is the answer I believe
Answer:
Id assume its 5 23/50..correct me if I'm wrong its been quite some time since I've dealed with decimals to fractions.
Step-by-step explanation:
That's a piecewise defined function and based on its definition we got the answer D.
(By combining -4≤x<2 and 2≤x≤10)
D. - 4 ≤ x ≤ 10
Answer:
The probability that Aaron goes to the gym on exactly one of the two days is 0.74
Step-by-step explanation:
Let P(Aaron goes to the gym on exactly one of the two days) be the probability that Aaron goes to the gym on exactly one of the two days.
Then
P(Aaron goes to the gym on exactly one of the two days) =
P(Aaron goes to the gym on Saturday and doesn't go on Sunday) +
P(Aaron doesn't go to the gym on Saturday and goes on Sunday)
- If Aaron goes to the gym on Saturday the probability that he goes on Sunday is 0.3. Then If Aaron goes to the gym on Saturday the probability that he does not go on Sunday is 1-0.3 =0.7
- Since the probability that Aaron goes to the gym on Saturday is 0.8,
P(Aaron goes to the gym on Saturday and doesn't go on Sunday) =
P(the probability that Aaron goes to the gym on Saturday)×P(If Aaron goes to the gym on Saturday the probability that he does not go on Sunday)
=0.8×0.7=0.56
- The probability that Aaron doesn't go to the gym on Saturday is 1-0.8=0.2
- And if Aaron does not go to the gym on Saturday the probability he goes on Sunday is 0.9.
Thus, P(Aaron doesn't go to the gym on Saturday and goes on Sunday) = P(The probability that Aaron doesn't go to the gym on Saturday)×P(if Aaron does not go to the gym on Saturday the probability he goes on Sunday)
=0.2×0.9=0.18
Then
P(Aaron goes to the gym on exactly one of the two days) =0.56 + 0.18 =0.74
