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irakobra [83]
3 years ago
9

Find the surface area of the square pyramid (above) using its net (below). 3

Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer

33

Step-by-step explanation:

11 of the faces is a square.

\begin{aligned} \text{Area of a square} &= \text{side} \cdot \text{side}\\\\ &= 3 \cdot 3\\\\ &= {\blueD{9}} \\\\ \end{aligned}

Area of a square

​

 

=side⋅side

=3⋅3

=9

​

Hint #22 / 4

444 of the faces are triangles. Each triangle has the same base and height.

\begin{aligned} \text{Area of a triangle} &= \dfrac12 \cdot \text{base} \cdot \text{height}\\\\ &= \dfrac12 \cdot 3 \cdot 4\\\\ &= 6 \\\\ \end{aligned}

Area of a triangle

​

 

=

2

1

​

⋅base⋅height

=

2

1

​

⋅3⋅4

=6

​

The total area of these 444 triangles is 4 \cdot 6 = \greenD{24}4⋅6=244, dot, 6, equals, start color #1fab54, 24, end color #1fab54.

Hint #33 / 4

Let's add the areas we found to find the surface area.

\begin{aligned} \text{Surface area} &= \blueD{9}+ \greenD{24}\\\\ &= 33\\\\ \end{aligned}

Surface area

​

 

=9+24

=33

​

Hint #44 / 4

The surface area of this square pyramid is 333333 units^2

2

squared.

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Mina says triangle A with angles
kotykmax [81]

Answer:

Yes, Mina is correct

Step-by-step explanation:

Let the triangles be A and B

Given

Triangle A:

Angles = 34, 57

Triangle B:

Angles = 89, 57

Required

Is Mina's claim correct?

First, we calculate the third angle in both triangles.

For A:

Third\ Angle = 180 - 34 - 57

Third\ Angle = 89

For B:

Third\ Angle = 180- 89 - 57

Third\ Angle = 34

For triangle A, the angles are: 34, 57 and 89

For triangle B, the angles are: 34, 57 and 89

<em>Since both triangles have the same angles, then by the postulate of AAA (Angle-Angle-Angle), the triangles are similar.</em>

3 0
3 years ago
Determine the gradient of the straight line 2x-3y+9=0. Find the equation of the straight line through the origin which is perpen
frutty [35]

Answer: 3

x

−

2

y

−

15

=

0

Explanation:

We know that,

the slope of the line  

a

x

+

b

y

+

c

=

0

is  

m

=

−

a

b

∴

The slope of the line  

2

x

+

3

y

=

9

is  

m

1

=

−

2

3

∴

The slope of the line perpendicular to  

2

x

+

3

y

=

9

is  

m

2

=

−

1

m

1

=

−

1

−

2

3

=

3

2

.

Hence,the equn.of line passing through  

(

3

,

−

3

)

and

m

2

=

3

2

is

y

−

(

−

3

)

=

3

2

(

x

−

3

)

y

+

3

=

3

2

(

x

−

3

)

⇒

2

y

+

6

=

3

x

−

9

⇒

3

x

−

2

y

−

15

=

0

Note:

The equn.of line passing through  

A

(

x

1

,

y

1

)

and

with slope

m

is

y

−

y

1

=

m

(

x

−

x

1

)3

x

−

2

y

−

15

=

0

Explanation:

We know that,

the slope of the line  

a

x

+

b

y

+

c

=

0

is  

m

=

−

a

b

∴

The slope of the line  

2

x

+

3

y

=

9

is  

m

1

=

−

2

3

∴

The slope of the line perpendicular to  

2

x

+

3

y

=

9

is  

m

2

=

−

1

m

1

=

−

1

−

2

3

=

3

2

.

Hence,the equn.of line passing through  

(

3

,

−

3

)

and

m

2

=

3

2

is

y

−

(

−

3

)

=

3

2

(

x

−

3

)

y

+

3

=

3

2

(

x

−

3

)

⇒

2

y

+

6

=

3

x

−

9

⇒

3

x

−

2

y

−

15

=

0

Note:

The equn.of line passing through  

A

(

x

1

,

y

1

)

and

with slope

m

is

y

−

y

1

=

m

(

x

−

Explanation:

the equation of a line in  

slope-intercept form

is.

∙

x

y

=

m

x

+

b

where m is the slope and b the y-intercept

rearrange  

2

x

+

3

y

=

9

into this form

⇒

3

y

=

−

2

x

+

9

⇒

y

=

−

2

3

x

+

3

←

in slope-intercept form

with slope m  

=

−

2

3

Given a line with slope then the slope of a line

perpendicular to it is

∙

x

m

perpendicular

=

−

1

m

⇒

m

perpendicular

=

−

1

−

2

3

=

3

2

⇒

y

=

3

2

x

+

b

←

is the partial equation

to find b substitute  

(

3

,

−

3

)

into the partial equation

−

3

=

9

2

+

b

⇒

b

=

−

6

2

−

9

2

=

−

15

2

⇒

y

=

3

2

x

−

15

2

←

equation of perpendicular lineExplanation:

the equation of a line in  

slope-intercept form

is.

∙

x

y

=

m

x

+

b

where m is the slope and b the y-intercept

rearrange  

2

x

+

3

y

=

9

into this form

⇒

3

y

=

−

2

x

+

9

⇒

y

=

−

2

3

x

+

3

←

in slope-intercept form

with slope m  

=

−

2

3

Given a line with slope then the slope of a line

perpendicular to it is

∙

x

m

perpendicular

=

−

1

m

⇒

m

perpendicular

=

−

1

−

2

3

=

3

2

⇒

y

=

3

2

x

+

b

←

is the partial equation

to find b substitute  

(

3

,

−

3

)

into the partial equation

−

3

=

9

2

+

b

⇒

b

=

−

6

2

−

9

2

=

−

15

2

⇒

y

=

3

2

x

−

15

2

←

equation of perpendicular line

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