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3 years ago

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Decimal 0.002 fraction percent

1 answer:

Eddi Din [679]3 years ago

5 0

0.2% becouse
0.002=2/1000=0.2/100

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George is 12 years older than Jeannie the sum of their ages in 5 years will be 50 how old is Jennie now

Bess [88]

Answer:

14 years old

Explanation:

Use this system of equations if G=George and J=Jeannie:

G-12=J

50=(G+5)+(J+5)

So, change second equation becomes

40-G=J

Then use substitution:

G-12=40-G

2G=52

G=26

Then, to find Jeannie’s age, go back to one of the equations and substitute G.

26-12=J

So, J=14

Jeannie is currently 14 years old.

4 0

3 years ago

Read 2 more answers

Write the point-slope form of the equation of the line that passes through the point (-1, 5) and has a slope of -1.

Anastaziya [24]

Point slope form = y - y1 = m (x - x1)

y - 5 = -1 (x -(-1))
y - 5 = -1 (x+1)

Hope this helps :)

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3 years ago

Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4

dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

$x_1\ =\ -2$

$y_1\ =\ 3$

$z_1\ =\ -4$

Distance is measure across the line

$\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}$

So, we can write

$\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k$

$=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k$

$=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k$

$=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}$

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

$3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3$

$=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18$

$=>18k-24+12k+9+10k-32\ =\ 18$

$=>\ k\ =\dfrac{13}{8}$

So,

$x\ =\ 3k-4$

$=\ 3\times \dfrac{13}{8}-4$

$=\ \dfrac{7}{4}$

$y\ =\ \dfrac{4k+3}{2}$

$=\ \dfrac{4\times \dfrac{13}{8}+3}{2}$

$=\ \dfrac{19}{4}$

$z\ =\ \dfrac{5k-16}{3}$

$=\ \dfrac{5\times \dfrac{13}{8}-16}{3}$

$=\ \dfrac{-21}{8}$

Now, the distance of point from the plane is given by,

$d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}$

$=\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}$

$=\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}$

$=\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}$

$=\ \sqrt{\dfrac{1177}{64}}$

$=\ 4.28$

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

= 8.56 unit

So, the distance of a point from it's image is 8.56 units.

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4 years ago

Write an equation in point-slope form of the line that passes through the given point and has the given slope.

MA_775_DIABLO [31]

12 square + 16 squared = c squared
144 + 256= c squared
400= c squared
C = 20

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3 years ago

254 words typed in 4 minutes

saveliy_v [14]

Answer:

63.5 words in 1 minute

Step-by-step explanation:

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4 years ago