The point P=\left(-\frac{\sqrt{33}}{7},\,\, y\right)P=(− 7 33 ,y) lies on the unit circle shown below. What is the value of
yy in simplest form?
1 answer:
Answer:
y = √-1040/7
Step-by-step explanation:
The equation of a unit circle is expressed as;
x²+y² = 1
Given the coordinate of P = (-33/7, y)
Substitute the coordinate into the give expression and find y;
(-33/7)²+y² = 1
Expand
y² = 1-(-33/7)²
According to difference of two square
y² = (1+(-33/7))1-(-33/7))
y² = (1-33/7)(1+33/7)
y² = -26/7(40/7)
y² = -1040/49
y= √-1040/49
y = √-1040/√49
y = √-1040/7
Hence the value of y is y = √-1040/7
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