Answer: Angle OZP= 62 Angle PZQ=63
(4r+2)+(5r-12)=125
9r-10=125
9r=135
r=15
Angle OZP Angle PZQ
4(15)+2 5(15)-12
62 63
What you do here is subtract g from f: x^2 - 5x + 8 - (x^2 -4); x^2 - 5x + 8 - x^2 + 4; Rearranging gives you x^2 - x^2 - 5x + 8 + 4 which is, simplified, -5x + 12
Another quadrilateral that you might see is called a rhombus. All four sides of a rhombus are congruent. Its properties include that each pair of opposite sides is parallel, also making it a parallelogram. In summary, all squares are rectangles, but not all rectangles are squares.
Answer:
1. 144 2. 16 3. 1 4. 3x-6
Step-by-step explanation:
So think of this as a function in a function. So you work from the inside to the outside. So for problem 1, we start with f(4)) [you read it "f of 4"] so what is the solution when x = 4, since f(x) means the function of x so f(4) means 'the function of 4' inside f(x).
Since f(x) = 3x then f(4) = 3(4) [notice how you substitute the 4 everywhere you see a letter x]
so f(4) = 12, now you work the next part h(f(4)) since f(4)=12 then h(12)
So take the h(x) function which is h(x) =
then h(12) =
so h(12) = 144
Let the number = x
It would be: 9x + 6 = 456
9x = 456 - 6
9x = 450
x = 450 / 9
x = 50
In short, Your Answer would be 50
Hope this helps!