<span>o,t,t,f,f,s,S,E,N,T,E,T </span>
<span>It's the first letter of all the numbers starting with one, two, three, four,... </span>
<span>The second pattern I might guess would be move the O back two spaces then move one space back, then repeat. </span>
<span>JKLMNO, JKLOMN, JKOLMN, OJKLMN, JKLMON, JKOLMN, ... </span>
<span>The second one I'm not sure about because there are only three starting terms to work with. It's hard to see the real pattern with that little to work with. </span>
<span>Hope this helps. </span>
What is the "children's story" if you tell me what that is I might be able to answer the problem
I’ll let u know as soon as i get the answer!! i did some work like this i think i can figure it out
Answer:
√1.45 = 1.2041594578792
Explanation:
Step 1:
Divide the number (1.45) by 2 to get the first guess for the square root .
Step 2:
Divide 1.45 by the previous result. d = 1.45/0.725 = 2.
Average this value (d) with that of step 1: (2 + 0.725)/2 = 1.3625
previous value = 0.725 - 1.3625 = 0.6375.
0.6375 > 0.001
Now we repeat the step
Step 3:
Divide 1.45 by the previous result. d = 1.45/1.3625 = 1.0642201835.
Average this value (d) with that of step 2: (1.0642201835 + 1.3625)/2 = 1.2133600918
Error = new guess - previous value = 1.3625 - 1.2133600918 = 0.1491399082.
0.1491399082 > 0.001.
Step 4:
Divide 1.45 by the previous result. d = 1.45/1.2133600918 = 1.1950285903.
Average this value (d) with that of step 3: (1.1950285903 + 1.2133600918)/2 = 1.2041943411 (new guess).
Error = new guess - previous value = 1.2133600918 - 1.2041943411 = 0.0091657507.
0.0091657507 > 0.001.
Step 5:
Divide 1.45 by the previous result. d = 1.45/1.2041943411 = 1.2041245757.
Average this value (d) with that of step 4: (1.2041245757 + 1.2041943411)/2 = 1.2041594584
- previous value = 1.2041943411 - 1.2041594584 = 0.0000348827.
0.0000348827 <= 0.001. accuracy, we stop the iterations and use 1.2041594584 as the square root.
