3x^2 -2root(6)x + 2 = 0
(root(3)x)^2 -2[root(3)x]root(2)+ (root(2))^2 = 0
let a = root(3)x and b = root(2)
a^2 -2ab + b^2 = 0
(a - b)^2 = 0
by the null factor rule,
a - b = 0
sub back in a and b
root(3)x = root(2)
x = root(3)/root(3)
Answer:y=6.61,x=-6.46
Step-by-step explanation:
3x+7y=-26(×5)
-
5x+3y=-14(×3)
=15x+35y=-130
-
15x+9y=-42
subtracting the 2 equations =15x-15x+35y-9y=-130-(-42)
=26y=172
y=172÷26
y=6.61
substitute y in the first equation=3x+6.61=-26
3x=-26+6.61=-19.39
x=-19.39÷3
x=-6.46
Answer:
1. 113
Step-by-step explanation:
(42+25)-180
You add the two numbers shown and subtract the product by 180
Answer:
a shared multiple of the denominators of several fractions.
Step-by-step explanation:
~AJTHESHOOTER...
Step-by-step explanation:
-4x(2x – 3) + 10x^2
