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2 years ago

13

Can someone help me with theses questions

2 answers:

oksian1 [2.3K]2 years ago

8 0

52 did the calculation

ollegr [7]2 years ago

5 0

Answer:

the last one is -21,375 feet

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Vince is trying to fit two boxes into the trunk of his car. One box is 1/2 of a foot tall and the other is 2 4/5 feet tall. Stac

Nitella [24]

Answer:

3 3/10

Step-by-step explanation:

In order to do this, you need to find the least common multiple. When you do that, you get 5/10 and 2 8/10. Next, what you what to do is turn 2 and 8/10 to an improper fraction, and when you do that you get 28/10. Add 28/10 and 5/10 to get 33/10. Simplify 33/10, and the correct answer is 3 3/10.

4 0

3 years ago

Read 2 more answers

Help me please!!!??<br>

Inessa [10]

Answer:

1/6

0.95833333333

Step-by-step explanation:

5 0

3 years ago

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Alisa has a bunch of coins. She has pennies. She has nickels. She has dimes. She has quarters. They lie in one big pile. Alisa w

Alona [7]

Answer:

E. Not enough info.

Step-by-step explanation:

There could be 2 quarters 500 nickels and 7 pennies or 800 pennies 50 quarters and 2 nickels.

3 0

3 years ago

Read 2 more answers

Triangle MNP is dilated according to the rule DO,1.5 (x,y)Right arrow(1.5x, 1.5y) to create the image triangle M'N'P, which is n

Vikki [24]

Given:

The vertex of a triangle MNP are M(-4, 6), N(2, 6), and P(-1, 1).

The rule of dilation is:

$(x,y)\to (1.5x,1.5y)$

The image of triangle MNP after dilation is M'N'P'.

To find:

The coordinates of the endpoints of segment M'N'.

Solution:

The end points of MN are M(-4, 6) and N(2, 6).

The rule of dilation is:

$(x,y)\to (1.5x,1.5y)$

Using this rule, we get

$M(-4,6)\to M'(1.5(-4),1.5(6))$

$M(-4,6)\to M'(-6,9)$

And,

$N(2,6)\to N'(1.5(2),1.5(6))$

$N(2,6)\to N'(3,9)$

The endpoints of M'N' are M'(-6, 9) and N'(3, 9).

Therefore, the correct option is B.

8 0

3 years ago

your patient has a 2500 cc bag of irrigation solution hanging, and 750 cc of fluid has been infused. what percentage of irrigati

nlexa [21]

Answer: 30%

Step-by-step explanation:

Given : Patient has a 2500 cc bag of irrigation solution hanging.

Irrigation has been infused = 750cc

Then, the percentage of irrigation solution has been infused :

$\dfrac{\text{ fluid infused}}{\text{Total irrigation solution}}\times100\\\\=\dfrac{750}{2500}\times100\\\\= 30\%$

Hence, the percentage of irrigation solution has been infused = 30%

6 0

3 years ago