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Setler79 [48]
3 years ago
13

Can someone help me with theses questions

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0
52 did the calculation
ollegr [7]3 years ago
5 0

Answer:

the last one is -21,375 feet

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Help ill give brainliest
stellarik [79]

Answer:

$28.68

Step-by-step explanation:

57.24+64.08

121.32

150-121.32

6 0
3 years ago
Read 2 more answers
Can I get help with these two please?
PSYCHO15rus [73]
Hi, hope this helps :)

3 0
4 years ago
Find all unit vectors that are orthogonal to the vector u = 1, 0, −4 .
KIM [24]

Answer:

Step-by-step explanation:

Given:

u = 1, 0, -4

In unit vector notation,

u = i + 0j - 4k

Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.

If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then

u. v = 0                    [<em>substitute for the values of u and v</em>]

=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k)  = 0               [<em>simplify</em>]

=> v₁ + 0 - 4v₃ = 0

=> v₁ = 4v₃

Plug in the value of v₁ = 4v₃ into vector v as follows

v = 4v₃ i + v₂ j + v₃ k              -------------(i)

Equation (i) is the generalized form of all vectors that will be orthogonal to vector u

Now,

Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

\frac{v}{|v|}

Where;

|v| = \sqrt{(4v_3)^2 + (v_2)^2 + (v_3)^2}

|v| = \sqrt{17(v_3)^2 + (v_2)^2}

\frac{v}{|v|} = \frac{4v_3i + v_2j + v_3k}{\sqrt{17(v_3)^2 + (v_2)^2}}

This is the general form of all unit vectors that are orthogonal to vector u

where v₂ and v₃ are non-zero arbitrary real numbers.

3 0
3 years ago
∠1 and ​ ∠2 ​ are vertical angles. ∠2 ​ has a measure of 31°. What is the measure of ​ ∠1 ​? Enter your answer in the box
leva [86]

For this case, the first thing you should know is that by definition, the vertical angles are congruent.

We have then:

∠1 and ∠2 are vertical angles.

Therefore, by definition:

∠1 = ∠2

On the other hand we have:

∠2 has a measure of 31 °.

Thus:

∠1 = ∠2 = 31 °

Answer:

the measure of ∠1 is:

∠1 = 31 °

7 0
3 years ago
Read 2 more answers
What is the area of this triangle? Enter your answer in the box. in² Triangle. Base is labeled 10 inches. A segment extending fr
Luba_88 [7]

Answer:

20 in³

Step-by-step explanation:

Area of a triangle is half the base times the perpendicular height:

A=0.5bh

=0.5*10*4

=20

3 0
3 years ago
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