Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.
- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )
E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
Answer:
a = -4
b = 5
c = -2
(That's the 3rd line you posted)
Step-by-step explanation:
Answer:
35 <5m
35/5 < 5m/5
7 < m
m = 8,9,10,11,12,.......
a + 6 
9
a + 6 - 6 9 -6
a 3
a = 3,4,5,6,7,......
8-g > 5
8 -g +g > 5 +g
8 > 5 +g
8 -5 > 5 -5 +g
3 > g
g =4,5,6,7,8.......
Step-by-step explanation:
The answer is choice A.
We're told that the left and right walls of the cube (LMN and PQR) are parallel planes. Any line contained in one of those planes will not meet another line contained in another plane. With choice A, it's possible to have the front and back walls be non-parallel and still meet the initial conditions. If this is the case, then OS won't be paralle to NR. Similarly, LP won't be parallel to MQ.
The answer to question 3 is 1 person orders chicken and the other 5 had steak dinner.
the way you work this out is you half 6 which is three and then do 3x14 and 3x17
3x14=42
3x17=51
42+51=93
this is too less so you have to do less of the cheaper meal (14) and more of the dearer one (17) so I went to 1x14 and 5x17
1x14=14
5x17=85
14+85=99
add these together and it makes 99
the answer to question 14 is 5 adults and 3 students
to do this you do exactly the same as how you do question 3
