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dangina [55]
3 years ago
12

What is one reason why a business may want to move entirely online?

Computers and Technology
1 answer:
andrezito [222]3 years ago
3 0

Answer:

To focus on global market

Explanation:

Hope this helps! :)

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Ways to ask for help effectively include
Step2247 [10]

Answer:

All of these choices

Explanation:

Clarity → the quality of being coherent and intelligible.

Sincerity → the quality of being free from pretense, deceit, or hypocrisy

Open mind → Open-mindedness is receptiveness to new ideas.

8 0
3 years ago
Create an Entity-Relationship Diagram with the following requirements.
melamori03 [73]

Answer:

idk

Explanation:

6 0
3 years ago
The official record of a high school student's performance is called:
Ivanshal [37]
The answer is transcript. When you apply for colleges and they want to see your high school records, they simply ask for your transcript. Hope I helped :)
5 0
3 years ago
Create the code that will find
frez [133]

Answer:

function findLongestWord(str) {

 var longestWord = str.split(' ').sort(function(a, b) { return b.length - a.length; });

 return longestWord[0].length;

}

findLongestWord(InputHere);

Explanation:

Replace InputHere with the input

7 0
3 years ago
Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the elemen
Verdich [7]

Answer:

Replace <STUDENT CODE> with

for (i = 0; i < SCORES_SIZE; ++i) {

       if(lowerScores.at(i)<=0){

           lowerScores.at(i) = 0;

       }

       else{

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Explanation:

To do this, we simply iterate through the vector.

For each item in the vector, we run a check if it is less than 1 (i.e. 0 or negative).

If yes, the vector item is set to 0

If otherwise, 1 is subtracted from that vector item

This line iterates through the vector

for (i = 0; i < SCORES_SIZE; ++i) {

This checks if vector item is less than 1

       if(lowerScores.at(i)<1){

If yes, the vector item is set to 0

           lowerScores.at(i) = 0;

       }

       else{

If otherwise, 1 is subtracted from the vector item

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Also, include the following at the beginning of the program:

<em>#include <vector></em>

8 0
3 years ago
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