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Alina [70]
3 years ago
9

Make greatest and smallest possible 7- digit number from 4,7,1,9,0,6,7​

Mathematics
2 answers:
Xelga [282]3 years ago
7 0

Answer:

greatest 9776410 smallest 1046779

Step-by-step explanation:

in smallest we cannot write 0 first because 0 has no units

Marysya12 [62]3 years ago
3 0

Answers:

Largest possible = 9776410

Smallest possible = 1046779

====================================================

Explanation:

To make the greatest 7-digit number, we start with the largest digit at the left-most end. So we start with 9. Then the next digit is the next largest, which is 7, and so on until we get

9776410

If we swap any two distinct digits, then we'll get something smaller than that value above. For instance, swap the 1 and 0 which leads to 9776401 and this is smaller than 9776410. This is simply because 01 is smaller than 10. Every other digit is kept the same. Try out other digit swaps to see that the result is smaller than the value in bold.

------------------------

To make the smallest 7-digit number, we just take the idea mentioned in the first section and we reverse it. We start with the smallest digit. We can't have 0 as the first value or else it won't be a 7-digit number. So we go for 1 instead. Then we can pick 0 next. For the third digit we pick the third smallest (the digit 4), and we build up to get

1046779

If we swap any distinct two digits, then we'll get something larger than this value. Let's say we swap the second 7 and the 9 at the end. We go from 79 at the end to 97. Since 79 < 97, this means 1046779 < 1046797. That's one example of many.

--------------------------

So in short, the largest number possible has all the largest digits to the left (and we decrease going left to right). The smallest number possible is the reverse of this having the smallest digits to the left (then increasing from left to right). The 0 cannot be at the left-most digit position, or else won't have a seven digit number.

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faltersainse [42]

Answer:

d=2.5

Step-by-step explanation:

first find the coordinate of B(mid point of AC):A(3,7) C(6,11)

d=√(6-3)²+(11-7)²

d=√3²+4²

d=√9+16=√25=5

since B is the mid point : d/2=5/2=2.5

<h2>Another way :</h2>

B(x1+x2/2 , y1+y2/2)   , x1=3 , x2=6, y1=7, y2=11

B(9/2,18/2)

B(9/2,9)

Find AB : the length or distance between 2 points:

d=√(x2-x1)²+(y2-y1)²

d=√(3-9/2)²+(7-9)²

d=√(-3/2)²+(-2)²

d=√1.5²+4

d=√6.25

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8 0
3 years ago
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior citizen tickets and 4 child ticke
FrozenT [24]

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?

14S + 4C = 200

14S = 200 - 4C

S = (200 - 4C)/14

7S + 1C = 92

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(200 - 4C)/14 = (92 - C)/7

7 x (200 - 4C) = 14 x (92 - C)

1400 - 28C = 1288 - 14C

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the price of one child ticket = $8

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Answer:

D) 4.01 miles

Step-by-step explanation:

2.87 miles from Monday + 1.14 miles =4.01 ran on Tuesday

5 0
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C would be your answer and here is how you would solve the problem.

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