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faust18 [17]
3 years ago
14

To use the HL Theorem to prove two triangles are congruent, the triangles must be right triangles. Which other conditions must a

lso be met?. . A.The triangles have congruent hypotenuses and two pairs of congruent legs. . B. The triangles have congruent hypotenuses and one pair of congruent legs. . C.The triangles have two pairs of congruent legs. . D. The triangles have congruent hypotenuses . .
Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0
The triangles have congruent hypotenuses and two pairs of congruent legs and this is the other condition that must also be met. The correct option among all the options that are given in the question is the first option or option "A". I hope that the answer comes to your help.
Hunter-Best [27]3 years ago
3 0

The triangles have congruent hypotenuses and two pairs of congruent legs and this is the other condition that must also be met. The correct option among all the options that are given in the question is the first option or option "A".

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Jamal planted 53 fewer flowers than Heidi. Write an expression to show how many flowers Heidi planted.
Sergeu [11.5K]

Answer:

y = x + 53

Step-by-step explanation:

Let x be the number of flowers Jamal planted and y the number of flowers Heidi planted.

Jamal planted 53 fewer flowers than Heidi:

x = y - 53

Isolate the y.

x + 53 = y (Change the - sign to + sign when switching from different sides of an equation)

y = x + 53

6 0
2 years ago
Read 2 more answers
Write v = 2x2 + 12x +1 in vertex form.
Savatey [412]

Answer:

C

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)²  + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = 2x² + 12x + 1

To express in vertex form use the method of completing the square.

The coefficient of the x² term must be 1 , thus factor out 2 from 2x² + 12x

y = 2(x² + 6x) + 1

add/ subtract ( half the coefficient of the x- term)² to x² + 6x

y = 2(x² + 2(3)x + 9 - 9) + 1

  = 2(x + 3)² - 18 + 1

  = 2(x + 3)² - 17 → C

6 0
3 years ago
Read 2 more answers
Sarah downloaded two apps which were 7.48 kb total. If one app was 4.78 kb, how big was the other app?
Keith_Richards [23]

Answer:

2.7 kb

Step-by-step explanation:

Total kb = 7.48

Total apps = 2

one app = 4.78

another app = x

> 4.78 + x = 7.48

x = 7.48 – 4.78

= 2.7 kb

3 0
3 years ago
Determine if the columns of the matrix form a linearly independent set. Justify your answer. [Start 3 By 4 Matrix 1st Row 1st Co
Volgvan

Answer:

Linearly Dependent for not all scalars are null.

Step-by-step explanation:

Hi there!

1)When we have vectors like v_{1},v_{2},v_{3}, ... we call them linearly dependent if we have scalars a_{1},a_{2},a_{3},... as scalar coefficients of those vectors, and not all are null and their sum is equal to zero.

a_{1}\vec{v_{1}}+a_{2}\vec{v_{2}}+a_{3}\vec{v_{3}}+...a_{m}\vec{v_{m}}=0  

When all scalar coefficients are equal to zero, we can call them linearly independent

2)  Now let's examine the Matrix given:

\begin{bmatrix}1 &-2  &2  &3 \\ -2 & 4 & -4 &3 \\ 0&1  &-1  & 4\end{bmatrix}

So each column of this Matrix is a vector. So we can write them as:

\vec{v_{1}}=\left \langle 1,-2,1 \right \rangle,\vec{v_{2}}=\left \langle -2,4,-1 \right \rangle,\vec{v_{3}}=\left \langle 2,-4,4 \right \rangle\vec{v_{4}}=\left \langle 3,3,4 \right \rangle Or

Now let's rewrite it as a system of equations:

a_{1}\begin{bmatrix}1\\ -2\\ 0\end{bmatrix}+a_{2}\begin{bmatrix}-2\\ 4\\ 1\end{bmatrix}+a_{3}\begin{bmatrix}2\\ -4\\ -1\end{bmatrix}+a_{4}\begin{bmatrix}3\\ 3\\ 4\end{bmatrix}=\begin{bmatrix}0\\ 0\\ 0\end{bmatrix}

2.1) Since we want to try whether they are linearly independent, or dependent we'll rewrite as a Linear system so that we can find their scalar coefficients, whether all or not all are null.

Using the Gaussian Elimination Method, augmenting the matrix, then proceeding the calculations, we can see that not all scalars are equal to zero. Then it is Linearly Dependent.

 \left ( \left.\begin{matrix}1 &-2  &2  &3 \\ -2 &4  &-4  &3 \\ 0 & 1 &-1  &4 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )R_{1}\times2 +R_{2}\rightarrow R_{2}\left ( \left.\begin{matrix}1 &-2  &2  &3 \\ 0 &0 &9  &0\\ 0 & 1 &-1  &4 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )\ R_{2}\Leftrightarrow  R_{3}\left ( \left.\begin{matrix}1 &-2  &2  &3 \\ 0 &1  &-1  &4 \\ 0 &0 &9  &0 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )\left\{\begin{matrix}1a_{1} &-2a_{2}  &+2a_{3}  &+3a_{4}  &=0 \\  &1a_{2}  &-1a_{3} &+4a_{4}  &=0 \\  &  &  &9a_{4}  &=0 \end{matrix}\right.\Rightarrow a_{1}=0, a_{2}=a_{3},a_{4}=0

S=\begin{bmatrix}0\\ a_{3}\\ a_{3}\\ 0\end{bmatrix}

3 0
3 years ago
The sides of a rectangle are a number and 4 less than that same numbers. The perimeter is 56. Find the dimensions of the rectang
VARVARA [1.3K]

Answer:

16m and 12m

Step-by-step explanation:

2x + 2(x - 4) = 56

4x = 64

x = 16

Sides are 16 m and 12 m

8 0
3 years ago
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