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faust18 [17]
3 years ago
14

To use the HL Theorem to prove two triangles are congruent, the triangles must be right triangles. Which other conditions must a

lso be met?. . A.The triangles have congruent hypotenuses and two pairs of congruent legs. . B. The triangles have congruent hypotenuses and one pair of congruent legs. . C.The triangles have two pairs of congruent legs. . D. The triangles have congruent hypotenuses . .
Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0
The triangles have congruent hypotenuses and two pairs of congruent legs and this is the other condition that must also be met. The correct option among all the options that are given in the question is the first option or option "A". I hope that the answer comes to your help.
Hunter-Best [27]3 years ago
3 0

The triangles have congruent hypotenuses and two pairs of congruent legs and this is the other condition that must also be met. The correct option among all the options that are given in the question is the first option or option "A".

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Max invests some money in a savings bond.
Mars2501 [29]

Answer:

£5650

Step-by-step explanation:

The money max invested in the saving bond = x

After one year the intrest will be 2% of x

Amount = £5763

Amount = Principcal + Interest

= £5763 = x + 2% multiplied x

£5763 = x + 2x/100

= 50x/50 + x/50 = 5763

= 51x/50 = £5763

51x = 5763x50

51x = 288, 150

x = 288,150/51

x = 5650

So the money max invested = £5650

7 0
2 years ago
PLS HELP ASAP PLS GIVE A GOOD EXPLANATION
taurus [48]
Negative integer.

-761 + 317= -444

Plug the answer in:

-761 - (-444)
= -317

Reminder: when multiplying two negatives, you get a positive.
4 0
3 years ago
Read 2 more answers
5,873
Tresset [83]

Answer:

1)5873 x 4=23492

2)5000 x 4=20000

3)800 x 4=3200

4)70 x 4=280

5)3 x 4=12

Step-by-step explanation:

4 0
2 years ago
What is it??????????
spayn [35]

Hey! :)

Some things to note: When you bring a exponent to the numerator, you make it negative.

When you put an exponent to another exponent, you multiply the exponents together.

(\frac{3x^2y^5}{x^6y^2} )^4\\\frac{81x^8y^{20}}{x^{24}y^8}\\81x^8x^{-24}y^{20}y^{-8}\\\frac{81y^{12}}{x^{16}}

so that is your answer, please let me know if you need more of an explanation. :)

8 0
3 years ago
I giv Brainliest
frutty [35]

Answer:

c

Step-by-step explanation:

3 0
2 years ago
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