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AysviL [449]
3 years ago
8

Which of the following equations is equivalent to 3(a - 5) = 4a ?

Mathematics
2 answers:
Nikitich [7]3 years ago
5 0

Answer:

2a = 15- a ..................

ahrayia [7]3 years ago
3 0
3(a-5)=4a
3a-15=4a
+15=+15
3a = 19a
•3. •3
=6
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viva [34]

Answer:1 11/12 CUPS OF TRAIL MIX

Step-by-step explanation:

1 1/2= 1 6/12

3/4=9/12

2/3=8/12

9/12+8/12=17/12=1 5/12

1 5/12+ 1 6/12= 1 11/12

5 0
3 years ago
Chapter 4, Final Chapter! - What is the Slope?
Minchanka [31]

Answer:

The Slope is -1/3

Step-by-step explanation:

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6 0
3 years ago
4x+6=4+(2x+1) is the answer 6=6
seropon [69]

Answer:

Step-by-step explanation:

4x+6=4+(2x+1)

Opening bracket

4x + 6 = 4 + 2x + 1

Collecting like terms

4x - 2x = 4 + 1 - 6

2x = -1

x = -1/2

4 0
3 years ago
Read 2 more answers
How do you get this to its Standard Form?<br>And is it linear?
Alchen [17]

let's bear in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient


so, let's do away with the denominators by multiplying both sides by the LCD of all fractions, in this case 6.


\bf \cfrac{x}{2}=\cfrac{y+3}{6}\implies\stackrel{\textit{multiplying by }\stackrel{LCD}{6}}{6\left( \cfrac{x}{2} \right)=6\left( \cfrac{y+3}{6} \right)}\implies 3x=y+3\implies \stackrel{\textit{standard form}}{3x-y=3}

4 0
4 years ago
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Find the equation of the line perpendicular to the<br> given line through the point (1,9). y=1/3x+5
Ivan

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be perpendicular, their slopes have to be the negative reciprocal of each other. (Basically flip the sign +/- and the fraction[switch the numerator and the denominator])

For example:

Slope = \frac{1}{3}

Perpendicular line's slope = -\frac{3}{1}  or  -3

Slope = -2 or -\frac{2}{1}

Perpendicular line's slope = \frac{1}{2}

y=\frac{1}{3} x+5    The given line's slope is \frac{1}{3}, so the perpendicular line's slope is -3. Now that you know the slope, substitute/plug it into the equation:

y = mx + b

y = -3x + b    To find b, plug in the point (1, 9) and isolate/get the variable "b" by itself in the equation

9 = -3(1) + b      Add 3 on both sides to get "b" by itself

9 + 3 = -3 + 3 + b

12 = b

y = -3x + 12

3 0
3 years ago
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