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3 years ago

what is the smallest number of integer kilogram weights needed to weigh every whole kilogram between 1kg and 40kg?

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

6 0

9514 1404 393

Answer:

Step-by-step explanation:

We assume you are using a balance, and that weights can be put in either pan. In that case, weight values can be either added or subtracted, so there are 3 possibilities for the contribution each weight makes. In other words, we need to find how many digits are required to count to 40 in base 3.

The largest 3-digit number in base 3 is ...

3^2 +3^1 + 3^0 = 13 (base 10)

The largest 4-digit number adds 3^3 = 27 to this: 27 +13 = 40.

Hence, we can weigh values 0 to 40 using 4 weights, of sizes 1, 3, 9, 27.

Some example weights are ...

5 = 9 - 3 - 1

38 = 27 + 9 + 3 - 1

where the "negative" weights are placed in the same pan as the unknown.

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3 years ago

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denpristay [2]

Answer:

166.27 m2

Step-by-step explanation:

area of hexagon = $\frac{3*\sqrt{3} }{2}$ * $a^{2}$ where a = length of 1 side

this hexagon is made of 6 equivalent triangle

consider ABC triangle

let AC length be x

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3 years ago

what is the smallest number of integer kilogram weights needed to weigh every whole kilogram between 1kg and 40kg?​

what is the smallest number of integer kilogram weights needed to weigh every whole kilogram between 1kg and 40kg?