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yawa3891 [41]
3 years ago
5

The table shows a linear function that the Hulk is using to study gamma rays.

Mathematics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

the corrrect answer is B

Step-by-step explanation:

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12) The answer is 2 months

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For a quadrilateral to be a square, the diagonals must be ________________.
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That bisect and are perpendicular

Step-by-step explanation:

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2 years ago
Is the following relation a function? (1 point)
Margarita [4]

If there are no repeating x values and an x value only goes to <em>one</em><em> </em>y value, then yes, it is a function.

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Can someone please help me Please I'm desperate
Yuri [45]

Answer:

James is 37, Rob is 44, and Kate is 35

Step-by-step explanation:

Set up an equation where x is James' age:

Rob's age can be represented by x + 7, since he is 7 years older than James

Kate's age can be represented by x - 2, since she is 2 years younger than James

Add these together in the equation and set it equal to 116:

(x + 7) + (x - 2) + (x) = 116

Add like terms and solve for x:

(x + 7) + (x - 2) + (x) = 116

3x + 5 = 116

3x = 111

x = 37

So, James is 37.

Find Rob's age by adding 7 to this:

37 + 7

= 44

Find Kate's age by subtracting 2:

37 - 2

= 35

So, James is 37, Rob is 44, and Kate is 35

4 0
3 years ago
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Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They
ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

P = 2

G = 3

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)

This gives:

P(G_1\ and\ G_2) = P(G_1) * P(G_2)

P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}

P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}

P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}

P(G_1\ and\ G_2) = \frac{3}{10}

P(P_1\ and\ P_2) = P(P_1) * P(P_2)

P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}

P(P_1\ and\ P_2) = \frac{1}{10}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)

P(Same) = \frac{3}{10} + \frac{1}{10}

P(Same) = \frac{3+1}{10}

P(Same) = \frac{4}{10}

P(Same) = \frac{2}{5}

8 0
3 years ago
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