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yarga [219]
2 years ago
6

PLEASE HELP

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
7 0

-1., 1, 2, 2

Step-by-step explanation:

A term is a single mathematical expression. It may be a single number (positive or negative), a single variable ( a letter ), several variables multiplied but never added or subtracted. Some terms contain variables with a number in front of them.

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Use the following algorithm:
andriy [413]

Answer:

First it says that you have to multiply the number x times 2, this will give you 2x as a result. Next you have to build your equation which is 2x=10, when you have an equation like this, you divide the result with the number before x (x=10÷2) your result will be x=5. Now you have to square the result (which is x) to get y, when squaring a number you have to multiply it by itself (depending of how many times it's asking to do so when there's a small number at the upper right corner of your number, that's how many times you multiply it) so if you have to square 5, it should be 5×5 which gives you the result of y being 25.

5 0
3 years ago
A) Work out 5% of 240
Pani-rosa [81]

Answer:

12 sorry if its wrong

Step-by-step explanation:

8 0
3 years ago
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I need the explanation too !
lubasha [3.4K]
<h2>Step-by-step explanation:</h2>

- 2y + x + 3 - 5x + 7 + 4y

=  - 2y + 4y + x - 5x + 7 + 3

=  2y -  4x + 10

THIS IS YOU'RE ANSWER

HOPE IT HELPS

MARK ME THE BRAINLIEST...

6 0
3 years ago
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Solve<br> 13/19-(-1/19)<br><br> a.-12/19<br> b.-14/19<br> c.14/19<br> d.12/19
mojhsa [17]

Answer:

C

Any time you have a subtraction and a negitive right next to eachother, it means to add. So, you would add 13 and 1 to get 14, then keep the denominator 19 to get 14/19.

Step-by-step explanation:

7 0
2 years ago
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To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
3 years ago
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