Answer:
The highest number on a die is 6. when we roll out two die the total sum cannot be more that 12. and each sum having the same probability of showing up.
The outcome of our experiment can be 2,3,4,5,6,7,9,10,11 or 12.
Step-by-step explanation:
Statistical experiment can be simply stated as the likelihood of an an event to occur or not.
Hey there!
It can be both. It's a multiple of 8 because 8 times 5 is 40, but it's also a factor of 120 because 80 times 3 is 120.
Hope this helps!
I = PRT....looking for T...re-arrange......I / PR = T
I / PR = T
I = 720
P = 1000
R = 9% = 0.09
now we sub
720 / (1000)(0.09) = T
720 / 90 = T
8 = T <===
3/7 because that is the number being added to the zero in the equation
Answer:
x= 12
Step-by-step explanation:
∠QPR +∠PQR= ∠HRQ (ext. ∠ of △PQR)
30° +(4x +2)°= (8 +6x)°
32 +4x= 8 +6x <em>(simplify)</em>
<em>Bring x terms on 1 side, constants to the other:</em>
6x -4x= 32 -8
2x= 24 <em>(</em><em>simplify</em><em>)</em>
x= 24 ÷2 <em> (÷2 on both sides)</em>
x= 12
<u>Method</u><u> </u><u>2</u><u>:</u>
∠PRQ= 180° -30° -(4x +2)° (∠ sum of △PQR)
∠PRQ= (148 -4x)°
∠PRQ +∠HRQ= 180° (adj. ∠s on a str. line)
(148 -4x)° +(8 +6x)°= 180°
148 -4x + 8 +6x= 180
156 +2x= 180
2x= 180 -156
2x= 24
x= 24 ÷2
x= 12