Answer:
The input value that produces the same output value in both charts is 2.
Step-by-step explanation:
You are given two functions
and
with tables
![\begin{array}{cc}x&f(x)\\-3&3.5\\-2&3\\-1&2.5\\0&2\\1&1.5\\2&1\\3&0.5\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7Dx%26f%28x%29%5C%5C-3%263.5%5C%5C-2%263%5C%5C-1%262.5%5C%5C0%262%5C%5C1%261.5%5C%5C2%261%5C%5C3%260.5%5Cend%7Barray%7D)
and
![\begin{array}{cc}x&g(x)\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7Dx%26g%28x%29%5C%5C-3%26%5C%5C-2%26%5C%5C-1%26%5C%5C0%26%5C%5C1%26%5C%5C2%26%5C%5C3%26%5Cend%7Barray%7D)
First, fill in the second table:
![g(-3)=2\cdot (-3)-3=-6-3=-9\\ \\g(-2)=2\cdot (-2)-3=-7\\ \\g(-1)=2\cdot (-1)-3=-5\\ \\g(0)=2\cdot 0-3=-3\\ \\g(1)=2\cdot 1-3=-1\\ \\g(2)=2\cdot 2-3=1\\ \\g(3)=2\cdot 3-3=3](https://tex.z-dn.net/?f=g%28-3%29%3D2%5Ccdot%20%28-3%29-3%3D-6-3%3D-9%5C%5C%20%5C%5Cg%28-2%29%3D2%5Ccdot%20%28-2%29-3%3D-7%5C%5C%20%5C%5Cg%28-1%29%3D2%5Ccdot%20%28-1%29-3%3D-5%5C%5C%20%5C%5Cg%280%29%3D2%5Ccdot%200-3%3D-3%5C%5C%20%5C%5Cg%281%29%3D2%5Ccdot%201-3%3D-1%5C%5C%20%5C%5Cg%282%29%3D2%5Ccdot%202-3%3D1%5C%5C%20%5C%5Cg%283%29%3D2%5Ccdot%203-3%3D3)
Hence, the second table is
![\begin{array}{cc}x&g(x)\\-3&-9\\-2&-7\\-1&-5\\0&-3\\1&-1\\2&1\\3&3\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7Dx%26g%28x%29%5C%5C-3%26-9%5C%5C-2%26-7%5C%5C-1%26-5%5C%5C0%26-3%5C%5C1%26-1%5C%5C2%261%5C%5C3%263%5Cend%7Barray%7D)
The input value that produces the same output value in both charts is 2.
common difference, d = -3
f1 = -13
An arithmetic sequence f(n) = f1 + d(n - 1)
so f(n) = -13 - 3(n - 1)
f(46) = -13 - 3(46-1) = -13 -3(45) = -13 - 135 = -148
Answer:
f(46) = - 148
If 4/5 of the total is 48, the total can be found by dividing it by 4 and multiplying it by 5:
48/4 = 12
12*5 = 60.
Answer:
The square root of 49 is 7. 7*7=49
Hope this helps,
:)