The maximum height of the function is 9
<h3>How to determine the maximum height?</h3>
The equation of the function is given as:
n=-1t^2 + 2t + 8
Differentiate the function
n' = -2t + 2
Set to 0
-2t + 2 = 0
Subtract 2 from both sides
-2t = -2
Divide both sides by -2
t = 1
Substitute t = 1 in n=-1t^2 + 2t + 8
n=-1(1)^2 + 2(1) + 8
Evaluate
n=9
Hence, the maximum height of the function is 9
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Answer:
A Is false, because that'd be 300.
B Is correct, because 9 rounded to the nearest is 10, plus the 300 original.
C I don't know what a unit is, but if it's ones value, then that's incorrect. It'd be 310.
D Incorrect, you can't round and have ".8"
E. Incorrect, can't round and have any decimal numbers...
Step-by-step explanation:
Answer:
b. day 2 is the farthest from 0
check the picture below.
so, those are the points, now, the line of symmetry, the red one, is the line that will cut the vertex is half and will be perpendicular to the opposite side.
now, the slope of the black line we can just get it off the grid, notice the rise and run, rise/run = 6/6 = 1.
now a perpendicular line to that one will have a negative reciprocal slope, thus
so the slope of that perpendicular line will be -1, so we're really looking for the equation of a line whose slope is -1 and runs through -6,3.
![\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad \qquad \qquad slope = m\implies -1 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=-1[x-(-6)] \\\\\\ y-3=-1(x+6)\implies y-3=-x-6\implies y=-x-3](https://tex.z-dn.net/?f=%20%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-6%7D~%2C~%5Cstackrel%7By_1%7D%7B3%7D%29%5Cqquad%20%5Cqquad%20%5Cqquad%20%20slope%20%3D%20%20m%5Cimplies%20-1%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-3%3D-1%5Bx-%28-6%29%5D%20%5C%5C%5C%5C%5C%5C%20y-3%3D-1%28x%2B6%29%5Cimplies%20y-3%3D-x-6%5Cimplies%20y%3D-x-3%20)
