Answer:
The value of r=
The value of x=
Step-by-step explanation:
Given that,
A) 
Now,

8(2r-2)=9(7r+10)
16r-16=63r+90
-16-90=63r-16r
-(16+90)=47r
-106=47r
r=
B) 
Now,

5(x+5)=9[3(x-2)-1]
5x+25=9[3x-6-1]
5x+25=9[3x-7]
5x+25=27x-63
25+63=27x+5x
83=32x
x=
i dont know my friend so try asking someone better than cause i have no brain for this type of math
Answer:
AD = 23
Step-by-step explanation:
The probability of it happening once is 1/5, since 10/50 simplifies to 1/5. Because the ticket goes back in the bag, the probability stays constant at 1/5.
For it to happen twice, you multiply the probability of it happening once, twice.
1/5 • 1/5 = 1/25 probability of it being Gary's name twice in a row.
Answer:
The prefix dodeca- means 12. I hope this helped! :-)