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vladimir1956 [14]
2 years ago
7

3(r+2)+5(2-r) =-32 can someone tell em the answer to that please

Mathematics
2 answers:
Alex17521 [72]2 years ago
8 0

Answer:

r = 24

Step-by-step explanation:

3(r+2)+5(2−r)=−32

Step 1: Simplify both sides of the equation.

3(r+2)+5(2−r)=−32

(3)(r)+(3)(2)+(5)(2)+(5)(−r)=−32(Distribute)

3r+6+10+−5r=−32

(3r+−5r)+(6+10)=−32(Combine Like Terms)

−2r+16=−32

−2r+16=−32

Step 2: Subtract 16 from both sides.

−2r+16−16=−32−16

−2r=−48

Step 3: Divide both sides by -2.

−2r/-2 = -48/-2

r = 24  

Kipish [7]2 years ago
5 0

Answer: r = 24

3(r+2)+5(2-r) =-32

this equals (if we do the multiplication)

3r+6+10-5r=-32

this equals  (if we simplify)

-2r+16=-32

this equals  (because we are subtracting from 1 side, we must subtract from the other)

-2r=-48

r=24

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olga55 [171]

Answer:

\text{Length of AB is }\frac{ah}{a+h}

Step-by-step explanation:

Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.

we have to find the length of AB.

Let the side of square i.e AB is x units.

As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°

⇒ CP||MP||AB

In ΔMNP and ΔCND

∠NCD=∠NMP     (∵ corresponding angles)

∠NDC=∠NPM     (∵ corresponding angles)

By AA similarity rule,  ΔMNP~ΔCND

Also, ΔKAP~ΔKPM by similarity rule as above.

Hence, corresponding sides are in proportion

\frac{ND}{NP}=\frac{CD}{MP} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{AB}{PM} \\\\\frac{ND}{NP}=\frac{x}{h} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{x}{h}\\\\\frac{NP}{ND}=\frac{h}{x} \thinspace\thinspace and\thinspace\thinspace \frac{KP}{KA}=\frac{h}{x}\\\\\frac{PD}{ND}=\frac{h}{x}-1 \thinspace\thinspace and\thinspace\thinspace \frac{AP}{KA}=\frac{h}{x}-1\\

KA(\frac{h}{x}-1)=AP

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Adding above two, we get

(KA+ND)(\frac{h}{x}-1)=(AP+PD)

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⇒ a-x=\frac{x^2}{h-x}

⇒ x^2=ah-ax-xh+x^2

⇒ x(h+a)=ah

⇒ x=\frac{ah}{a+h}

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