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2 years ago

Please help me understand this, i've been stuck on this question

Mathematics

1 answer:

Drupady [299]2 years ago

4 0

A is correct.
to find the average, you add up all three test scores, divide the sum by 3
85≤(83+91+n)/3≤90

multiply 3 to eliminate the fraction: 255≤(174+n)≤270
subtract 174: 81≤n≤96

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Hi everyone can someone help me out with this question please

luda_lava [24]

A) After any given year the amount of money would be: [(1000*.04)x]+1000
and x stands for the number of years.
B) The interest is 4%.
C) There would be $3,480.00 after 4 years.

5 0

2 years ago

ABCD is a rhombus. Find AC

jolli1 [7]

ABC my as I don’t know

6 0

2 years ago

I need help in learning how to solve this equation using substitution:

Tomtit [17]

Answer:

x=3, z=-1, y=6

Step-by-step explanation:

you need to make the coefficients of each variable equal to each other then subtract 2 equations.

this one: multiply -4 in 1st

4x+4y+4z=32

-4x+4y+5z=7

_____________

8x+0-z=25

we have 2 equations with 2 variables now

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4 0

2 years ago

Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a

Mashutka [201]

Answer:

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

Step-by-step explanation:

Given

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Required

Make the denominator equal

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Factorize the denominator

$\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}$

$\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}$

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

$\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}$

$\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}$

$\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}$

<em>The expression now have the same denominator</em>

7 0

2 years ago

In part a, you determined that you can make 40 servings from five packages of buns and four packages of hot dogs without anythin

pentagon [3]

ceiling(700/40) = ceiling(17.5) = 18 . . . . ceiling(x) is the smallest integer ≥ x.

The smallest integer multiple of 40 that is larger than 700 is 18.

The number of packages of buns will be 18*5 = 90.

The number of packages of hotdogs will be 18*4 = 72.

_____

These numbers will ensure that you have 20 bun/hotdog combinations left over. If you want to minimize leftovers, you would use 88 packages of buns and 70 packages of hotdogs. That would give you 4 buns and no hotdogs left over.

7 0

3 years ago