Question

Mrs. Rouse has three times as many gladiolus as Mrs. Leal together they have 128 gladiolus write the system of equations for this situation ?

Answer 1

R = # of Gladiolus Mrs. Rouse has
L = # of gladiolus Mrs. Leal has

R = 3L
R+L = 128

Solution for number of Gladiolus each has

3L + L = 128

4L = 128

L = 32

R = 3(32) = 96