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ycow [4]
3 years ago
11

Mrs. Rouse has three times as many gladiolus as Mrs. Leal together they have 128 gladiolus write the system of equations for thi

s situation ?
Mathematics
1 answer:
natka813 [3]3 years ago
3 0
R = # of Gladiolus Mrs. Rouse has
L = # of gladiolus Mrs. Leal has

R = 3L
R+L = 128

Solution for number of Gladiolus each has

3L + L = 128

4L = 128

L = 32

R = 3(32) = 96
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2 years ago
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