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photoshop1234 [79]
3 years ago
6

URGENT.. pls help NO links

Mathematics
1 answer:
Svetllana [295]3 years ago
7 0

Answer:

.83

Step-by-step explanation:

we want

(sports∩Senior)/Senior

we can see that sports∩senior= 25

and senior= 25+5+5=30

25/30= .83

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A scale model of a bus is 12 inches long<br> . How many inches long is the bus it represents
lions [1.4K]

Answer: 304.8 milimeter

Step-by-step explanation:

7 0
3 years ago
Type the correct answer in the box. Use numerals instead of words.
aleksley [76]

Answer:

28080$

Step-by-step explanation:

there are 52 weeks in a year.

15x10= 150

150x52=7800

13x30= 390

390x52= 20280

20280+7800= 28080

7 0
3 years ago
a square has a side length of 18 feet. the square was dilated by a scale factor of 1/2 to create a new square. what is the side
dexar [7]
The side length of the new square would be 9. When you dialate you multiply by the square factor, so 1/2 times 18 equals 9.
8 0
4 years ago
Read 2 more answers
What is the value of (5.3 times 10 Superscript 4 Baseline) (4.2 times 10 Superscript 3) in scientific notation?
katovenus [111]

Answer:

2.226X 10^8

Step-by-step explanation:

We are to determine the value of (5.3 X 10^4) (4.2 X 10 ^ 3) in scientific notation.

Given:

(5.3 X 10^4) (4.2 X 10 ^ 3)

STEP 1: Remove the brackets.

(5.3 X 10^4) (4.2 X 10 ^ 3)=5.3 X 10^4X4.2 X 10 ^ 3

STEP 2: Separate the numbers and index of 10.

=5.3  X4.2X 10^4 X 10 ^ 3

STEP 3: Multiply the Numbers and Index of 10

=22.26X 10^{4+3}

STEP 4: Simplify and write in Scientific notation

22.26=2.226X10\\Therefore:\\22.26X 10^{4+3}=2.226X10X 10^{4+3}=2.226X10X 10^7=2.226X 10^8

Thus:

(5.3 X 10^4) (4.2 X 10 ^ 3)=2.226X 10^8 in scientific notation

6 0
3 years ago
Read 2 more answers
(4y^2-3y+2)+(5y+12y-4)-(13y^2-6y+20)
Andrews [41]

Answer:

-(9 y^2 - 20 y + 22) or if you need y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

Step-by-step explanation:

Simplify the following:

-(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2

Grouping like terms, -(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2 = -(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4):

-(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4)

-3 y + 5 y + 12 y = 14 y:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + (2 - 4)

2 - 4 = -2:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + -2

-(13 y^2 - 6 y + 20) = -13 y^2 + 6 y - 20:

-13 y^2 + 6 y - 20 + 4 y^2 + 14 y - 2

Grouping like terms, 4 y^2 - 13 y^2 + 14 y + 6 y - 20 - 2 = (-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2):

(-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2)

4 y^2 - 13 y^2 = -9 y^2:

-9 y^2 + (6 y + 14 y) + (-20 - 2)

6 y + 14 y = 20 y:

-9 y^2 + 20 y + (-20 - 2)

-20 - 2 = -22:

-9 y^2 + 20 y + -22

Factor -1 out of -9 y^2 + 20 y - 22:

Answer: -(9 y^2 - 20 y + 22)

______________________________________________

Solve for y:

-9 y^2 + 20 y - 22 = 0

Divide both sides by -9:

y^2 - (20 y)/9 + 22/9 = 0

Subtract 22/9 from both sides:

y^2 - (20 y)/9 = -22/9

Add 100/81 to both sides:

y^2 - (20 y)/9 + 100/81 = -98/81

Write the left hand side as a square:

(y - 10/9)^2 = -98/81

Take the square root of both sides:

y - 10/9 = (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

y = 10/9 + (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

Answer: y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

4 0
3 years ago
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