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3 years ago

15

Solving linear systems graphically

1 answer:

Mekhanik [1.2K]3 years ago

4 0

Answer:

Step-by-step explanation:

You graph both functions and the point where the two lines intersect is ur solution.

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Solve 2cos x+2cos 2x=0 on the interval [0,2pi)

rjkz [21]

$2cosx+2cos2x=0 \\ -2sin^2x+2cos^2x+2cosx=0 \\ -2(1-cos^2x)+2cos^2x+2cosx=0 \\ -2+2cos^2x+2cos^2x+2cosx=0 \\ 4cos^2x+2cosx-2=0 \\ t=cos x \\ 4t^2+2t-2=0 \\ \Delta=4+32=36 \\ t_1= \frac{-2-6}{8}=-1 \\ t_2= \frac{-2+6}{8}= \frac{1}{2} \\ cos x=-1 \lor cos x= \frac{1}{2} \\ x=-\pi \lor x= \frac{5\pi}{3}$

6 0

2 years ago

Read 2 more answers

What are the coordinates of the point that is one half the distance between A(−3, −5) and B(2, 7)?

Olenka [21]

Answer:

$(\frac{-1}{2},1)$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

<u>Step 1: Define</u>

A (-3, -5)

B (2, 7)

<u>Step 2: Find midpoint</u>

Substitute: $(\frac{-3+2}{2},\frac{-5+7}{2})$
Add: $(\frac{-1}{2},\frac{2}{2})$
Divide: $(\frac{-1}{2},1)$

3 0

3 years ago

I don't know how to work this out

Serhud [2]

Hope that helped I use this when I'm doing math. It's called cymath it explain how they got the answer.

8 0

3 years ago

The measure of angle 1 is (10x+8)° and the measure of angle 3 is (12x- 10)°.

12345 [234]

Step-by-step explanation:

option b ie. 98 degree

if you do angle 2 +10x+8=180

from 10x +8 and 12x -10 we can get the value of X

7 0

1 year ago

Need help with this please

Shtirlitz [24]

The ricipricals are 3/8 and 2/13

7 0

3 years ago