Select the fraction greater than 7/9. a)4/5 b)2/3 c)13/18 d)3/5

Mathematics

1 answer:

Fiesta28 [93]3 years ago

5 0

Answer:

A)4/5

Step-by-step explanation:

7/9=0.778

so you need to convert the other fractions into decimals as well. The one that's greater than 0.778 will be your answer.

a)4/5=0.8

b)2/3=0.667

c)13/18=0.722

d)3/5=0.6

The decimal that's greater than 0.778 is A=0.8 so that's the answer.

You might be interested in

There are 500 rabbits in Lancaster on February 1st. If the amount of rabbits triples every month. Write a function that represen

Anuta_ua [19.1K]

Answer:

10,93,500.

Step-by-step explanation:

On first February total number of rabbits were 500.

Now it is given that after each month rabbit population will become triple of initial.

So, after one month rabbits will become 3×500.

After two months they will become $3^{2}$ ×500.

Thus , after m months total number of rabbits will become $3^{m}$ ×500.

Now,

On August 1 , 7 months will get passed from February 1 so putting m = 7 in the equation we get ,

Total number of rabbits = $3^{7}$ ×500 = 10,93,500.

8 0

3 years ago

The number of text messages sent daily by a student is a poisson random variable with parameter λ=5 .in a class with 20 independ

Rudik [331]

This problem is a combination of the Poisson distribution and binomial distribution.

First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961

For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181

7 0

3 years ago

Some help me please i have 9 questions

Lyrx [107]

awnser:

m<3=50

Step-by-step explanation:

seen in the picture if you need help let me know