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-BARSIC- [3]
3 years ago
7

Consider solving 푥2+12푥+5=0by completing the square. What number should be added to both sides of the equation? 푥2+12푥+_____=−5+

_____a. -36b. 36c. 16d. -16
Mathematics
1 answer:
ANTONII [103]3 years ago
3 0

Answer:

B. 36

Step-by-step explanation:

The equation in question is not well written. Let the equation be;

x²+12x+5 = 0

In order to know what number should be added to both sides of the equation, we will take the square of the half of coefficient of x as shown;

Coefficient of x = 12

Half of 12 = 1/2(12) = 6

Square of 6 = 6² = 36

Hence the required number to add to both sides of the equation by completing the square method is 36

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Part (i)

I'm going to use the notation T(n) instead of T_n

To find the first term, we plug in n = 1

T(n) = 2 - 3n

T(1) = 2 - 3(1)

T(1) = -1

The first term is -1

Repeat for n = 2 to find the second term

T(n) = 2 - 3n

T(2) = 2 - 3(2)

T(2) = -4

The second term is -4

<h3>Answers: -1, -4</h3>

==============================================

Part (ii)

Plug in T(n) = -61 and solve for n

T(n) = 2 - 3n

-61 = 2 - 3n

-61-2 = -3n

-63 = -3n

-3n = -63

n = -63/(-3)

n = 21

Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).

<h3>Answer:  21st term</h3>

===============================================

Part (iii)

We're given that T(n) = 2 - 3n

Let's compute T(2n). We do so by replacing every copy of n with 2n like so

T(n) = 2 - 3n

T(2n) = 2 - 3(2n)

T(2n) = 2 - 6n

Now subtract T(2n) from T(n)

T(n) - T(2n) = (2-3n) - (2-6n)

T(n) - T(2n) = 2-3n - 2+6n

T(n) - T(2n) = 3n

Then set this equal to 24 and solve for n

T(n) - T(2n) = 24

3n = 24

n = 24/3

n = 8

This means 2n = 2*8 = 16. So subtracting T(8) - T(16) will get us 24.

<h3>Answer: 8</h3>
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3 years ago
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