Andrew can buy maximum 3 meals this weekend.
From given question,
Andrew must spend less than 53$ on meals during the weekend.
He has already spent 21$ on meals costing 8$ average.
Let x, the number of meals
So, we get an inequality,
8x + 21 < 53
We need to find the number of meals he can buy this weekend.
From above inequality,
⇒ 8x + 21 < 53
⇒ 8x < 53 - 21
⇒ 8x < 32
⇒ x < 4
This means, from 1 to 3 meals.
Therefore, Andrew can buy maximum 3 meals this weekend.
Learn more about an inequality here:
brainly.com/question/19003099
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Answer:
AB-C^2 = 3x^3 + x^2 + 9
Step-by-step explanation:
Hi
AB = (x^2)*(3x+2)= 3x^3 + 2x^2
C^2= (x-3)^2 = x^2 - 9
So
AB-C^2 = 3x^3 + 2x^2 - x^2 + 9 = 3x^3 + x^2 + 9
The answer to number one is C
and the answer to number two is A
What is the probability that a student with a GPA below 3.0 does not enjoy school?
Only 15/60 below 3.0 enjoy school.
Rounded, that equals 25%.
Therefore, there is a 75% probability that a student with a GPA below 3.0 does not enjoy school.
