Answer:
Step-by-step explanation:
Let X be the random variable for the time needed to grade a randomly chosen first examination paper
X is N(5, 4)
a)
Time taken=11.00-6.50=4hours 10 min=25/6 hours
P(X<25/6) =P(Z<![\frac{\frac{25}{6}-5 }{4} =P(Z](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B25%7D%7B6%7D-5%20%7D%7B4%7D%20%3DP%28Z%3C-0.21%29)
=0.5-0.0832=0.0168
b) Time >11.10-6.50 = 4 hours 20 mint = 13/3 hours
P(X>13/3) = P(Z>-0.16) = 0.5636
Area= 190
height= 2(width) - 1
area= length times width
190= (2(width) -1) x width
190 = 2w^2-w
w^2-w-190 = 0
use quadratic fomula, you'll get w= 10
so height will be 2(10)-1 = 19
6m²+3,. also 3(2m²+1), depending on what the question actually wants for an answer
Answer:
-43
Step-by-step explanation:
just plug in -9 for x and solve
g(-9)=4(-9)-7
=-43
Answer:
s.jnufdhgvsgvru
Step-by-step explanation: