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Shalnov [3]
3 years ago
9

If a Swoog can Swig, and a Swig can Swoog, can a Swoog Swig, a Swig Swoog?

Mathematics
2 answers:
alisha [4.7K]3 years ago
6 0

Answer:

Yes?

Step-by-step explanation:

Mademuasel [1]3 years ago
5 0

Answer:

C. yes loll :P

Step-by-step explanation:

Hav a good day

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Match the terms to their definition.
erastova [34]
6 = able to be divided evenly without a remainder
4 = the line between the numerator and denominator of a fraction
5 = a fraction in which the numerator is larger than or equal to the denominator
9=fractions with the same numerical value; fractions that are equal to each other
7 = a number that has more factors than just 1 and itself
1= a number that divides evenly into another number
10= an organized way of finding the prime factorization of a number
8= a number that shows part of a whole
2 =the largest factor that any given numbers have in common
3= the number under the fraction bar tells how many equal parts the whole was broken into


4 0
3 years ago
Explain why this number 523.691 has different value
mezya [45]
It has a decimal making it have different value. Without the decimal it is a whole number. Its not really an explanation, but stuff like that is hard to explain.
8 0
3 years ago
Rodney had 7 toffees MORE than Micah. Micah’s father then gave him 2 more toffees. How many toffees more than Micah would Rodney
WARRIOR [948]

Answer:

Rodney will have 9 toffees more than Micah.

Step-by-step explanation:

Let the numbr of toffee Micah have = x

So, the number of toffee Rodney have = x + 7.

Since, Micah's father gave him 2 more toffees.

Then, number of toffee Micah now have = x + 2

<em>So, number of toffees Rodney will have = (x+7) + 2 = x + 9.</em>

Hence, Rodney will have 9 toffees more than Micah.

5 0
3 years ago
PLEASE HELP ASAP!!!!! i’ll mark brainlest
hoa [83]

Answer:

It would be hundreds

Step-by-step explanation:

I hope it is right :I

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
irina1246 [14]

5x^3 - 4x + 1 = 0 \\\\5x^3-5x+x+1=0\\\\5x(x^2-1)+1(x+1)=0\\\\5x(x+1)(x-1)+1(x+1)=0\\\\(x+1)(5x(x-1)+1)=0\\\\(x+1)(5x^2-5x+1)=0\\\\x=-1\\\\5x^2-5x+1=0\\\\\Delta=(-5)^2-4\cdot5\cdot1=25-20=5

\Delta>0 therefore there exist two real solutions.

In total, there are 3 real roots. But, real roots are also complex roots (doesn't work the other way round!), so there are 3 complex roots.

8 0
3 years ago
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