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grandymaker [24]
2 years ago
10

alt="\frac{3}{4}-\frac{2}{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Komok [63]2 years ago
8 0
Lcf= 12


So we’d have
9 - 8
———
12

1
—-
12
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A business associate who owes Ana $4,000 offered to pay her $3,800 now or to pay her $2,000 now and $2,000 two years later. Usin
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I think it will be 11,800 all u do is add
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The graph below shows the height an elevator travels, y, in x seconds:
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9514 1404 393

Answer:

  25 (ft/s)

Step-by-step explanation:

The "rate of change" is taken to mean the "rise" divided by the "run". Here, adjacent points differ in their y-value by 25 ft and their x-value by 1 second.

The rate of change is ...

  rise/run = (25 ft)/(1 second) = 25 ft/second

Usually, we're just interested in the numerical value: 25.

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<em>Additional comment</em>

The graph is mis-labeled. It is not showing "rate of ascent." It is showing height as a function of time. The "rate of ascent" is the <em>slope</em> of the line on the graph, not its <em>value</em>.

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2 years ago
What number must you add to complete the square?<br> X2+8x=-3<br> A. 8<br> B. 16<br> C. 4<br> D. 64
GREYUIT [131]

Answer:

I think it is 16

4 0
3 years ago
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This is a picture of a cube and the net for the cube.
makvit [3.9K]

I cant give you the answer without the picture but I can tell you how to solve it.

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3 years ago
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a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
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