Homework due this midnight :0 √∛∛∡∡↓⇄⊃↓→↔
2 answers:
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Solution (1)
for k=0 / for k=1 / for k=-1
x=0 / x=2π / x=-2π
acc / acc / rej
solution (2)
for k=0 / for k=1 / for k=-1
x=0 / x=2π/3 / x=-2π/3
acc / acc / rej
Note that i'm trying values of K which make the answer belong to our interval;
So our solution which i will represent as a set is;
S € {0,2π/3,2π}
Answer:
The resulting graph is .
Step-by-step explanation:
The resulting function is of the form:
Where:
- Independent variable, dimensionless.
- Dependent variable, dimensionless.
- Amplitude, dimensionless.
- Midpoint value, dimensionless.
The sine function is bounded, between -1 and 1, and must be multiplied by a stretch factor. That is: . According to the graph, the function is bounded between 5 (
) and -5 (
), and the midpoint value (
) is 0. The amplitude is determined by the following calculation:
If and
, then:
The resulting graph is .