Answer:
The bolts with diameter less than 5.57 millimeters and with diameter greater than 5.85 millimeters should be rejected.
Step-by-step explanation:
We have been given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.71 millimeters and a standard deviation of 0.08 millimeters.
Let us find the sample score that corresponds to z-score of bottom 4%.
From normal distribution table we got z-score corresponding to bottom 4% is -1.75 and z-score corresponding to top 4% or data above 96% is 1.75.
Upon substituting these values in z-score formula we will get our sample scores (x) as:


Therefore, the bolts with diameters less than 5.57 millimeters should be rejected.
Now let us find sample score corresponding to z-score of 1.75 as upper limit.


Therefore, the bolts with diameters greater than 5.85 millimeters should be rejected.
By using a graphing calculator, the solutions are:
(-3, 4) and (1, 0)
Answer:
b. x² + 8x + 12 =
1. use the factoring X (see attachment)
2. 6 x 2 = 12; 6 + 2 = 12
3. (x + 6)(x + 2) = 0
4. x = -6, -2
c. x² + 13x + 12 =
1. 12 x 1 = 12; 12 + 1 = 13
2. (x + 12)(x + 1) = 0
3. x = -12, -1
c. x² + x - 12 =
1. 4 · (-3) = -12; 4 - 3 = 1
2. (x +4)(x - 3) = 0
3. x = -4, 3
f. x² + 15x + 36 =
1. 12 x 3 = 36; 12 + 3 = 15
2. (x + 12)(x + 3) = 0
3. x = -12, -3
hope this helps :)
36,700, it stays the same
If it were like that, 9/20 would be baseball card.

x=27 since 20x3=60