Is the address 7b invalid regarding cell references?
1 answer:
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Answer:
Check the explanation
Explanation:
Note : check attached image for output and program and also note that you're to replace "at" with shift 2 as the brainly text editor can't take the symbol
Program : **************Magzine.java**********************
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
public class Magzine {
//class variable private can not access outside class
private String title;
private String month;
private int year;
//parameterized constructor
public Magzine(String title,String month,int year)
{
this.title=title;
this.month=month;
this.year=year;
}
//override toString method
"at"Override
public String toString()
{
String detail=title+" "+month+" "+Integer.toString(year);
return detail;//return string of class variable
}
//get Magzine objecte
public boolean equals(Magzine obj)
{
//commented returm statement compare string by address so you can uncomment if
//we do not use same string object of String class
//return this.month==obj.month && this.title==obj.title && this.year==obj.year;
//compare two object element if matches return true else false
return (this.month.equals(obj.month)) &&(this.title.equals(obj.title)) && this.year==obj.year;
}
}
Program : *************************Main.java****************************
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
public class Main {
/**
* "at"param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
Magzine Obj =new Magzine("Scientific American ", "April", 2020); //object of class
Magzine Obj1 =new Magzine("Scientific American ", "April", 2020);//Obj and obj1 is same content data
Magzine Obj2 =new Magzine("Scientific American", "June", 2020); //obj and obj1 same but obj2 different
System.out.println(Obj.toString()); //print string of obj
System.out.println(Obj1.toString());//print string of obj1
System.out.println(Obj2.toString());//print string of obj2
System.out.println(Obj.equals(Obj1)); //obj and obj1 equal and return true
System.out.println(Obj.equals(Obj2)); // obj and obj2 not equal so return false
}
}
Output can be seen below:
